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In natural units you fix only two dimensional constants, which means that you still have one 'unfixed' dimension with which to measure units. Certain physical quantities (velocity, action and their po …

If $\hbar = c = 1$ then length is time, and mass is inverse length or inverse time. This is correct. In this way, since $[G]=[M^{-1}L^3T^{-2}]$ in SI units, its dimensionality reduces to $$ [G] =[M^ …

In a word: No. The Bohr radius is a key concept and it is not deprecated. In the modern outlook, the Bohr radius is the length unit of the atomic system of units, i.e., it is the natural length scale …

This is mostly to make an explicit connection with natural units - the unit system in which $\hbar$ and $c$ are both set to 1, which is the natural set of units for relativistic quantum theory. Becaus …

If you're setting $\hbar=1$, then you don't - you can't - distinguish between energy and angular frequency. They are, in fact, the same quantity, since $E=\hbar\omega=\omega$. Similarly, if $\hbar=1$ …

$\mathrm{MeV/fm^3}$ is a unit of energy density and a unit of pressure in SI-compatible units. In its full glory, it goes \begin{align} 1\:\mathrm{MeV/fm^3} & = 10^6\:e \:\mathrm V/(10^{-15}\:\mathrm …

This is in essence the de Broglie relation, $$p=\frac h\lambda,$$ rephrased in a more useful form in terms of the wavenumber $k=2\pi/\lambda$ and the reduced Planck constant as $$p=\hbar k,$$ and then …

Planck units is the unit system in which $\hbar=c=G=k_B=1$. In high-energy physics, temperature is often left out, and we don't care about gravity, so we work by setting only $\hbar=c=1$. This system …