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One can express that in terms of torque and angular momentum $\vec{L}_r$ relative to the center of mass $$ \frac{d \vec{L}_r}{dt} = \sum_i \vec{d}_i \times \vec{F}_{i,\text{ext}} \tag2 $$ with $\vec{L} …

But I guess the most severe problem will be this torque applied to the astronaut if the momentum is not directed towards the center of mass, which leaves him spinning if no counter-torque can be upheld … Conservation of angular momentum demands $$ L = \Theta \cdot \omega = R \cdot p_{\text{bullet}} $$ for the astronauts angular momentum and therefore $$ T = \frac{2\pi}{\omega} = \frac{\pi \cdot m \cdot …

If a charged particle is accelerating, it "borrows" some of his momentum and energy to the EM-field which is then radiated as EM-waves carrying this momentum and energy. …

v) \cdot m c \\ - m \cdot \gamma(v) \cdot \vec{v} } \right) = \left( \matrix{0 \\ \vec{0}} \right) $$ The new dynamical quantities are $ \vec{p} = m \cdot \gamma(v) \cdot \vec{v}$, which we may call momentum …

If that transformation is translation in time translation in space rotation around an axis the conserved quantity is energy momentum in direction of that translation angular momentum in direction … So for instance if a physical process is "invariant" (see below for further clarification) under translation in any direction, the momentum in any direction is conserved. …