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Results tagged with newtonian-mechanics
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user 380387
Newtonian mechanics discusses the movement of classical bodies under the influence of forces by applying Newton’s three laws. For more general concepts, use [classical-mechanics]. For Newton’s description of gravity, use [newtonian-gravity].
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How does the radial component of acceleration not change the linear speed of a body in circu...
1.Acceleration is defined as rate of change of velocity. In this case, suppose you have constant magnitude of velocity. However, centripetal force is still required for the object to continue moving i …
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Banked Corners and Centripetal Forces Question
Here if you resolve normal reaction into components:
$$Nsin\theta=mg$$
$$Ncos\theta=\frac{mv²}R$$
and on simplifying the second equation you get
$$v=\sqrt{Rgtan\theta}$$
You'll notice that there is on …
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What is the velocity of centre of mass in centre of mass frame?
From ground frame, the centre of mass does have a velocity. From the reference frame of the centre of mass itself, its (relative) velocity is zero.
Imagine you are standing on the ground, and a car p …
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Is a body in uniform circular motion in equilibrium?
Equilibrium means that the net force on the body on any chosen axis is zero. A body in uniform circular motion has constant magnitude of velocity, but its direction is continuously changing (always ta …
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Rotating a rolling-without-slipping wheel in the direction that makes the contacting point h...
Rolling without slipping in that would not not possible on a stationary platform, however on a platform moving with 2v, rolling without slipping can still take place.
The whole point of rolling withou …
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Centre of masses of 2 bodies together
It is correct. What you're actually saying is:
$$\frac{ab+cd}{a+c}=\frac{a\frac{ab}{a}+c\frac{cd}{d}}{a+c}$$
Where a is mass of the rod, b is the coordinate of its center of mass, c is mass of the cur …
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Normal Force and Newton's Third Law
"Push on the table by the book." said force in your question is gravitational force, between the earth and the book, with a magnitude equal to its weight $mg$. The normal by the table is due to Newton …
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Acceleration on a system of two particles
Internal forces are those forces which are applied on both the particles, of equal magnitudes and opposite directions.That being said, in answer to your query:it depends on what the forces are. The te …
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On which side of object should friction force be drawn on a vector diagram?
Force is a vector quantity. Parallel shifting of vectors is allowed while judging translational motion. You can pretty much put that arrow anywhere on the block so long as you know it is actually appl …
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answers
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Work done in raising an object to a height
When we raise an object to a height $h$, it is said that the potential energy of the object is increased by $mgh$. But isn't the work done by gravitational force $-mgh$?
Then that will essentially mea …
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How can we prove that tension on both sides of string will be equal?
The string is massless and inextensible; so if there is a net force on any part of the string it will cause its acceleration.
Since m approaches zero, acceleration for even a small unbalanced force wi …
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Formula for Work
You can't just ask the formula for work without specifying
You can ask the formula for work done by the force on the object, which would be $Fscos\theta$, where F is the magnitude of said force. This …
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Can't understand inelastic collisions
Kinetic energy, during a collision, is lost, for eg., as sound energy. If there is no dissipation of energy in any manner (sound/heat/light) we call it an elastic collision, and then you can conserve …
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Formation process of parabola in rotating water cup
Assume water rotating in a cylindrical bucket:
I will take a random 'cylinder' of water from this(and treat it as separate from the rest of the liquid)
Then drawing FBD of that cylindrical 'block' of …
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What is the acceleration experienced by a person walking into a tree or pole?
Well, if someone walks into a pole, their velocity goes from $0.80 m/s$ to $0 m/s$ in a very small time interval, so acceleration would be infinite, since time approaches zero. With the work-energy me …
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