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For an (ice) crystal to form it needs to have a starting point to form around, that is called the Nucleation point. Liquids can be in a non stable state where they are supercooled but they can not mak …

In classical thermodynamics, we usually start with defining the exact differential of the property we want to examine (because we are interested mostly in differences) rather than exact quantities. …

I want to derive it like this, because I am not yet familiar so much with statistical mechanics, but I know classical thermodynamics and I wonder if this derivation is "legal" (whatever that means). …

I understand that every body of some temperature above the absolute zero radiates EM waves. When we heat it up enough it enters the visible spectrum and than proceeds to go upwards to higher and highe …

Is that something from classical thermodynamics or can it be shown only outside of it? …

I have found even another way. Let's imagine an arbitrary polytropic process, and work $W_{12}$ is done by the system and heat $Q_{12}$ is given to the system. Than the polytropic index follows from: …

Now if we construct similar diagrams in the Hamiltonian formalism to the ones that are known in thermodynamics, namely $p,V$ and $T,S$ we would get $H,t$ and $p,q$ diagrams. …

I understand that there is an explanation in thermodynamics that goes as follows: The change from liquid to solid is a process that makes a less ordered system in to a more ordered system (potential violation …

I want to derive the maximum (free) work function $M$: $$M=U_1-U_2 +p_s(V_1-V_2) -T_{s}(S_1-S_2)$$ where the variables with the index $1$ represent the initial state of the system and the variables la …

I was deriving the equations for calculating the entropy change $\Delta S_M$ of the system where ideal gases are being mixed. The first one utilizes partial pressures via Dalton's law: $$\Delta S_M= \ …

.$$ You start, of course, from the first law of thermodynamics: $$\delta Q=-dU$$ the heat that a body gives away results in a decrease of its internal energy. …

I believe I have found another way. Consider a hypothetical process in an open system and let's say that the power supplied to do some polytropic process (a compression in this case, as power is being …

In the pV diagram an isochoric curve is, of course, a vertical line whereas in the T-s diagram it has the form: $$T(s)=T_0 \space e^{\frac{s-s_0}{c_V}}\tag1$$ so it is an exponential function (steeper …

I am reading Planck's work on black-body radiation. In the paper on the page 19 it is said that the expression $$R_\nu=\frac{\nu^2}{c^2}U\tag1$$ where $R_\nu$ is the intensity of a linearly polarised …

The Clausius (in)equality is as you stated: $$dS \ge \frac{\delta Q}{T_{surr}}\tag1$$ where the equality holds for reversible procesess. Using the fundamental thermodynamc relation: $$dU=TdS-pdV$$ we …