Search Results
| Search type | Search syntax |
|---|---|
| Tags | [tag] |
| Exact | "words here" |
| Author |
user:1234 user:me (yours) |
| Score |
score:3 (3+) score:0 (none) |
| Answers |
answers:3 (3+) answers:0 (none) isaccepted:yes hasaccepted:no inquestion:1234 |
| Views | views:250 |
| Code | code:"if (foo != bar)" |
| Sections |
title:apples body:"apples oranges" |
| URL | url:"*.example.com" |
| Saves | in:saves |
| Status |
closed:yes duplicate:no migrated:no wiki:no |
| Types |
is:question is:answer |
| Exclude |
-[tag] -apples |
| For more details on advanced search visit our help page | |
Results tagged with forces
Search options not deleted
user 306389
This tag is for the classical concept of forces, i.e. the quantities causing an acceleration of a body. It expands to the strong/electroweak force only insofar as they act comparable to ‘classical’ forces. Use the [particle-physics] tag for decay channels due to forces and [newtonian-mechanics] or one of the other subtopics of [classical-mechanics] for the dynamics of classical systems.
2
votes
Accepted
Why are dependancies multiplied when a physical quantity is dependant on two different quant...
When we say $F$ is directly proportional to $M_1$, we mean that keeping other things/factors constant, $F$ will change by as much as $M_1$ changes.
This keeping other things/factors constant part is c …
- 154
1
vote
Accepted
How does a simple pendulum gain its acceleration?
You explained it almost correctly in your last paragraph. I'm elaborating it to explain exactly what happens when $F$ is removed.
The moment the horizontal $F$ is removed, tension $T$ changes to $T'$ …
- 154
1
vote
How can there be force with no work if $W = Fd$ and $F = ma$?
If there is a net force, there will be a net acceleration.
Acceleration means there is going to be displacement, and now there is a possibility of work.
Possibility because though force dictates curre …
- 154