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It's the physical property that indicates the degree/intensity of heat present in a substance or an object. It can be expressed and measured according to various scales.

3 votes

Why do we need Legendre transformation for thermodynamic potentials?

If we didn't use Legendre transform, we would waste precious information. Consider the case of a function of one variable for simplicity: $y=g(x)$. Now what you propose to do is to define $t=\frac{dg} …
Salvatore Manfredi D's user avatar
6 votes
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Why do we need Legendre transformation for thermodynamic potentials?

For example, temperature is much easier to control. This is why Helmoltz free energy is introduced: $F=F(T,V,N)$ having in mind that $T=\left(\frac{\partial U}{\partial S}(S,V,N)\right)_{V,N}$. …
Salvatore Manfredi D's user avatar