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Partial differential equation which describes the time evolution of the wavefunction of a quantum system. It is one of the first and most fundamental equations of quantum mechanics.
0
votes
Accepted
Time-independent constant-Hamiltonian Schrodinger equation solution when at time 0 there's a...
Usually, you have to write your 2d lattice in 1-d array, and the $\exp(iHt/\hbar)$ a 2d matrix.
For example, I have 2d lattice $2 \times 2$
$$
\begin{matrix}
(1,1) & (1, 2) \\
(2, 1) & (2 …
1
vote
Born-Oppenheimer approximation: calculating the expectation values for the molecular hamilto...
Question: can the term $\phi_N T_N \phi_e$ be neglected?
$${T_N}| \phi_N \phi_e \rangle = \phi _e T_N \phi_N + \phi_N T_N \phi_e - \hbar^2 \sum_\alpha {1 \over M_\alpha}{\vec \nabla_\alpha} \cdot \{ \ …
3
votes
Schrödinger equation in energy basis
Let's first recall the process of emergence of the momentum schrödinger equation, strating from the time-independent schrödinger equation. We make a Fourier transformation in time, then obtain a spati …
1
vote
Physical significance of a wavefunction with a discontinuous derivative
The relation of the first derivative of the wave function is meant to keep the flux of propability constant across the interface. Therefore, if the effectice masses are different across a heterojuncti …
2
votes
Bound state of Hydrogen atom at large $r$
The properties of a physical system depends on the boundary condition as well as the governing equations. All eigen vlaues are results from a giving boundary condition.
Therefore, it is to be kept in …
2
votes
How to solve double delta potential bound states by "brute force"
Let's write wave functions in these three regions for a level of energy $-E, E>0$. The corresponding exponent of wavefunction is $q = \sqrt{\frac{2 m E}{\hbar^2}}$:
Region 1: $x < -a$
$$
\Psi_1(x) …
0
votes
Constancy of Wronskian when potential has Finite Discontinuities
Starting from your equation:
$${\Psi^*(x)}\,(d^2\Psi(x)/dx^2)-(d^2{\Psi^*(x)}/dx^2)\,\Psi(x)=0$$
You are just one-step away from the answer:
\begin{align}
0 &= {\Psi^*(x)}\,(d^2\Psi(x)/dx^2)-(d^2{\Psi …