Search Results

First, the $\rho'(\vec r)$ is not correct. I change it to the following $\rho_2$ in Eq.(2), for $r<b$ by the step function $\Theta(b-r)$. The equestion is what is the different between the following t …

Starting from the given potential: $$ {\newcommand{\r}{\vec{r}}} \phi_2(\r) = \frac{1}{4\pi\varepsilon_0} \sum_{ij} \frac{3r_ir_j - r^2\delta_{ij}}{r^5}Q_{ij} \tag{1}$$ First examine \begin{align} \ …

Let's write wave functions in these three regions for a level of energy $-E, E>0$. The corresponding exponent of wavefunction is $q = \sqrt{\frac{2 m E}{\hbar^2}}$: Region 1: $x < -a$ $$ \Psi_1(x) …

Since $\delta(x)$ is not an operational function, it can only be defined by a limiting process. Your variation is in fact including two limiting processes. For multi-limiting processes, the order of t …

Because there is a $\delta(r-a)$ in the $\rho(\vec{r})$, therefore as long as the integral is concerned, these two expressions give same answer to the result of integration. They can be differentiate …