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Within relativity (both special and general), changes of reference frames can change both the notions of space and of time, with one depending on the other as well. As a consequence, it is necessary to treat both concepts in a unified manner. Hence the term spacetime.
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Understanding this spacetime diagram
That is a conformal diagram representing the Haggard-Rovelli spacetime. The thick line represents the collapsing/bouncing null shell. …
1
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Does an expanding universe naturally induce a Lorentzian metric in local nonexpanding coordi...
What you are referring to its a known fact, which is that you can see a Lorentzian metric as a Riemannian metric with the addition of a causal structure given by an everywhere nonzero line field. The …
0
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How to relate Riemannian and Lorentzian tetrad fields on the same manifold/spacetime?
Why are you assuming that $\eta_{ab} = (\mathbb{I}_{ab}-2l_{a}l_{b})$?
The quantity $\mathbb{I}_{ab}-2l_{a}l_{b}$ gives you a Lorentzian metric, but could be different from Minkowski. For example, you …
5
votes
Accepted
Why in physics we work with metric without defining topology/smooth structure first?
Here $\mathbb{R}^3_0$ is $\mathbb{R}^3$ minus the origin and $\mathbb{R}^{+}$ the positive real numbers.The topology can be chosen to be the manifold topology defined by the atlas or (because the spacetime … However, there are other cases where details matter: if topological and, therefore, global aspects of spacetime are discussed, as in singularity theorems, the roles are reversed, and the metric plays a …
0
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Junction Conditions: In what cases is matching the extrinsic curvature at a boundary tantamo...
If $x^{\mu}$ are the spacetime coordinates and $y^{a}$ the hypersurface coordinates it could happen that (especially in symmetric situations)
\begin{equation}
K_{ab} =n_{\alpha} \left( \frac{\partial^{ …
0
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Non-Compactness in Penrose Singularity
For example, in any spacetime that is asymptotic at spatial infinity to Minkowski space, a Cauchy hypersurface (if there is one) is not compact. …
2
votes
Accepted
A question on the causal hierarchy/ladder and the existence of CTC
A strongly causal spacetime do not contains CTCs. …
2
votes
Accepted
Derivation of the Schwarzschild metric: why are $g_{22}$ and $g_{33}$ the same as for flat s...
The Schwarzschild solution is a spherically symmetric solution produced by a central source. This means that at $t = \mathrm{const}$ the metric should be invariant under rotations.
\begin{equation}
d …
2
votes
Accepted
A question about the topology of spacetime and the existence of CTCs
You have already noticed that the two topologies coincide if and only if the spacetime is strongly causal. … Moreover in the case where spacetime is not strongly causal the Alexandrov topology ceases to be Hausdorff. …
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Why do we defer to GR when describing black holes rather than rely on QM?
When we say that general relativity and quantum mechanics are not compatible, we mean a number of different circumstances. For example, by linearizing the Einstein-Hilbert action, one can obtain a leg …