Search Results
| Search type | Search syntax |
|---|---|
| Tags | [tag] |
| Exact | "words here" |
| Author |
user:1234 user:me (yours) |
| Score |
score:3 (3+) score:0 (none) |
| Answers |
answers:3 (3+) answers:0 (none) isaccepted:yes hasaccepted:no inquestion:1234 |
| Views | views:250 |
| Code | code:"if (foo != bar)" |
| Sections |
title:apples body:"apples oranges" |
| URL | url:"*.example.com" |
| Saves | in:saves |
| Status |
closed:yes duplicate:no migrated:no wiki:no |
| Types |
is:question is:answer |
| Exclude |
-[tag] -apples |
| For more details on advanced search visit our help page | |
Results tagged with linear-algebra
Search options not deleted
user 251599
To be used for linear algebra, and closely related disciplines such as tensor algebras and maybe clifford algebras.
6
votes
3
answers
450
views
Why does it matter that a passive transformation can be "interpreted" as an active transform...
In most mathematics textbooks I have read (see e.g. Axler), the change of basis (COB) matrix has been introduced as a useful computational tool for expressing components of vectors in different bases. …
- 1,261
1
vote
1
answer
131
views
Commuting normal operators have common eigenbasis?
One often finds in quantum mechanics textbooks (for physicists) a "proof" that self-adjoint and commuting operators $A,B$ have a common eigenbasis. However, in the standard proof of Bloch's theorem (s …
- 1,261
4
votes
2
answers
862
views
Why this definition of the trace?
It is common in quantum mechanics textbooks (e.g. Ballentine page 15) to define the trace of an operator as the sum of its diagonal elements in an orthonormal basis in particular. Why is this definiti …
- 1,261