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Propagating solutions to Maxwell’s equations in classical electromagnetism and real photons in quantum electrodynamics. A superset of thermal-radiation.

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Why the energy of electromagnetic waves is directly proportional to frequency whilst for mec...

i am not a physics major but substitute $$ \lambda = \frac{c}{f}\,\, $$ in this equation $$ E=\frac{1}{2}\mu A^2\omega^2 \lambda $$ will give you E as a function of frequency not frequency squared wh …
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