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Distributions are generalized functions, such as, e.g., the Dirac delta function. DO NOT USE THIS TAG for statistical probability distributions, profiles, graphs, plots, etc.

16 votes

Physical meaning of the Jacobian in relation to Dirac delta function

We can handle easily integrals where the vector variable of integration, let $\:\mathbf{u}\:$, is the argument of the $\:\delta-$function, for example \begin{align} \iiint\d …
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3 votes
Accepted

Why does it follow that the Dirac delta function is a scalar "because determinant of the Lor...

So we want to prove that the expression $\,\delta^4\left[\boldsymbol{x-x}\left(\tau\right)\right]\,$ is a Lorentz invariant scalar, that is \begin{align} & \delta^4\left[\boldsymbol{x'}\boldsymbol{- …
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5 votes

Derivative of delta function

The Dirac $\;\delta\;$ function is even. This is more clear looking it as limit of proper functions. While its 1rst derivative is an odd function.
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1 vote
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How to evaluate the coordinate transformation of Dirac delta function?

Of course we can evaluate the given integral without transforming the Dirac $\delta-$functions since : \begin{equation} \int\limits_{\boldsymbol{-\infty}}^{\boldsymbol{+\infty}}\!\!\delta\left(x_{_{\r …
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3 votes
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Greiner's Green's function for diffusion

Let a real function $\;f(x)\;$ of the real variable $\;x\in\mathbb{R}\;$ for which \begin{align} f(x)\boldsymbol{=}0 \quad & \text{for any} \quad x\boldsymbol{\ne} x_{0} \quad \textbf{and} \tag{01a}\l …
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2 votes

The gradient of the d'Alembertian Green's function

We need frequently to differentiate expressions of Dirac $\delta$-function when the argument of the latter is a function $f\left(z\right)$ of the variable $z$ with respect to which we want to differen …
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3 votes

Transition probability derivation: How to prove $\lim_{\alpha\rightarrow\infty} \frac{\sin^2...

Consider a real function $\;f(x)\;$ of the real variable $\;x\in\mathbb{R}\;$ for which \begin{align} f(x)\boldsymbol{=}0 \quad & \text{for any} \quad x\boldsymbol{\ne} x_{0} \quad \textbf{and} \tag{0 …
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4 votes
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Why is the propagator the Green's function for Schrodinger equation?

Hint : Check if this "modified" Schrodinger equation is satisfied by the "modified" propagator \begin{equation} \widetilde{K}(\mathbf{x''},t \; \boldsymbol{;} \;\mathbf{x'},t_{0})=\theta(t-t_{0})\;K …
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6 votes
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Normalization of eigenfunction to Dirac-delta function

For a function $f(x)$ the Fourier transform is defined as: \begin{equation} \overset{\boldsymbol{\sim}}{f}\left(k\right)=\dfrac{1}{\sqrt{2\pi}}\int\limits_{\boldsymbol{-}\infty}^{\boldsymbol{+}\infty} …
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1 vote
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Heaviside function in the form of an integral

$\newcommand{\bl}[1]{\boldsymbol{#1}} \newcommand{\e}{\bl=} \newcommand{\p}{\bl+} \newcommand{\m}{\bl-} \newcommand{\mr}[1]{\mathrm {#1}} \newcommand{\gr}{\bl>} \newcommand{\les}{\bl<} \newcommand{\g …
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13 votes

Divergence of $\frac{ \hat {\bf r}}{r^2} \equiv \frac{{\bf r}}{r^3}$, what is the 'paradox'?

You must use the Dirac $\:\delta-$function and its properties. The point charge $\:q\:$ being at rest at $\:\mathbf{r}_{0}\:$ we have \begin{equation} \mathbf{E}\left(\mathbf{r},t\right)\boldsymbol{= …
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