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Fermions are particles with an intrinsic angular momentum (i.e. spin) equal to a "half integer" number of fundamental units: $\frac{(2n+1)}{2} \hbar$ for integer $n$. Fermions are required to be in a quantum state that is globally anti-symmetric, which leads to the Pauli Exclusion Principle barring identical fermions from occupying the same quantum state.
0
votes
About fermionic particles and bosonic particles in RQFT, ST
pmatrix}
0\\
1\\
0\\
0\\
\end{pmatrix}
$
$ u^{3} $
$
\begin{pmatrix}
0\\
0\\
1\\
0\\
\end{pmatrix}
$
$ u^{4} $
$
\begin{pmatrix}
0\\
0\\
0\\
1\\
\end{pmatrix}
$
and the associated wavefunctions of the fermions …
0
votes
About fermionic particles and bosonic particles in RQFT, ST
to electron and positron (matter and anti-matter), Dirac do just this separation for the Hamiltonian to find two equation one of electron(matter) the other for positron(anti-matter).
by other side the fermions …
0
votes
About fermionic particles and bosonic particles in RQFT, ST
Dirac equation is an equation for the relativistic quantum ave function of a single electron.\
we shall regard the dirac wave function as a field, which will subsequently be quantized along with the …
0
votes
Fermion propagator as derivative of scalar propagator
The $ \Gamma $ matrices can be constructed recursively,
d = 2
Using the Pauli matrices,
$ \gamma _{0}=\sigma _{1}$, $\gamma _{1}=-i\sigma _{2}$
where the two gamma matrices can be given by
$ \Gamm …
-2
votes
Fermion propagator as derivative of scalar propagator
Sorry your question is strange for me gamma matrices defined in two dimensions!!!! where you find this subject?
Pauli spin matrices
\begin{equation}
\sigma^{i} = (\sigma^{1}, \sigma^{2}, \sigma^{3 …
0
votes
Fermion propagator as derivative of scalar propagator
This answer is from my lecture of QFT That i prepared i wish you find what you want, let me know.
It is prefer to write the collision between to particles in term of \textit{amplitude} of \textit{prob …
0
votes
Fermion propagator as derivative of scalar propagator
\subsection{Spenor feynman Propagator}
consider the operator field $ b\psi $ to creat a virtual particle at event y, and $ \psi $ to destroy that virtual particle particle at even x. The spinor propag …