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So there must be some power loss like a normal resistor ($I^2R$) does in a circuit. But the power loss is $0$. How is this possible? Suppose the voltage $V(t)$ supplied by the AC voltage is …

I thought of something about Electromechanical Energy Conversion No, you need to consider the Lorentz force. Especially see Lorentz force - Force on a current-carrying wire. The force acting on a pi …

Kirchhoff's circuit laws can be derived from general electrodynamics together with the approximation called Lumped-element model for electrical systems. For deriving Kirchhoff's voltage law we start …

Yes, you misunderstood the meaning of unit-prefixes. The milli prefix is by definition identical to a factor of $0.001$. Therefore, in the fraction you can cancel them just like you can cancel normal …

Consider this circuit mimicking your lab situation. You have a DC voltage source ($U=10 \text{V}$), a switch, a volt-meter, a really big coil (with a high inductance $L_\text{coil}=1\ H$, and a low r …

First, the simulation tells the truth. The transient behavior at the beginning is not an error. As @BobD already suggested, do not begin with looking at the simulation result. Instead, you should cho …

With your meter you can measure only the rms of voltage and current, but not their phases. Therefore from the complex impedance $$\frac{V}{I}=Z=i\omega L+R$$ you can only measure its absolute value $$ …

For an inductor (with inductance $L$) the defining relation between voltage ($V$) and current ($I$) is: $$V(t)=L\frac{dI(t)}{dt} \tag{1}$$ To find the total energy $E$ fed into the inductor you need t …

How is energy transported at the speed of light if electrons don't flow like very fast water? Let me reply with the hydraulic analogy, i.e. with replacing electrical current by water flow. Ope …

Your calculation is correct so far. But instead of $V(t)=V_0\sin(\omega t)$ start with $V(t)=V_0e^{j\omega t}$. And then repeat your calculation to find $I(t)$.

As the the other answers already said: When you read "a resistor reduces the current", this does not mean, that the current after the resistor is smaller than before the resistor. Instead it means, th …

A typical charger looks like this (the part marked with a red frame): (image from ElectroSchematics - simple 12 volt charger The functional parts of this charger are a transformer (transforming from …

Remember, voltage is defined to be the potential difference between two points. Now consider the two resistors in series. Then it is easy to see, that the potential difference (i.e. the voltage) betw …

A real battery always has an internal resistance (typically between $0.1\ \Omega$ and $0.3\ \Omega$). Therefore, when you connect more light bulbs, then the total current and hence the voltage across …

You can certainly do such experiments. But bear in mind: For the relation $R=\rho l/A$ to be true, the current flow needs to be homogenous between the electrodes and neglectable outside this region. T …