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It's the physical property that indicates the degree/intensity of heat present in a substance or an object. It can be expressed and measured according to various scales.

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How do you convert 4180 $\rm{J \cdot kg^{-1} K^{-1} to~ J\cdot kg^{-1} C^{-1}}$?

This is a trick question! Notice that the unit of Kelvin is essentially the same for the unit for Celsius, but is based around a different zero point. That is, an increase in one degree Celsius is the …
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