Search Results
| Search type | Search syntax |
|---|---|
| Tags | [tag] |
| Exact | "words here" |
| Author |
user:1234 user:me (yours) |
| Score |
score:3 (3+) score:0 (none) |
| Answers |
answers:3 (3+) answers:0 (none) isaccepted:yes hasaccepted:no inquestion:1234 |
| Views | views:250 |
| Code | code:"if (foo != bar)" |
| Sections |
title:apples body:"apples oranges" |
| URL | url:"*.example.com" |
| Saves | in:saves |
| Status |
closed:yes duplicate:no migrated:no wiki:no |
| Types |
is:question is:answer |
| Exclude |
-[tag] -apples |
| For more details on advanced search visit our help page | |
Results tagged with units
Search options not deleted
user 131694
Units are standards of measurement used for different types of quantities.
0
votes
Accepted
How is the unit of kinetic energy equivalent to $\mathrm{Pa}\cdot\mathrm{m}^3$?
As you know unit of kinetic energy is Joule
where
$$\rm Joule=N\cdot m$$
But from pressure equation $P=F/A$
$$\rm 1N=Pa m^2$$
Putting this into $J= N\cdot m$
$$\begin{align}J &=Pa ~\mathrm{m^2\tim …
- 34