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In introductory mechanics, the momentum of a particle is its mass times its velocity. In electrodynamics, the momentum of a field is proportional to the cross-product of the electric field with the magnetic field. In special relativity, momentum is generalized to four-momentum.

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Relativistic particle decay in ZMF [closed]

Edit1: So far, relating $E^2 = (pc)^2 + (mc^2)^2$ and considering conservation of 4-momentum has given me $2(pc)^2+c^4(m_1^2+m_2^2)+2E_1E_2=(Mc^2)^2$ which doesn't seem obviously solvable. … Other attempts have given that $(\gamma_1^2-1)m_1^2=(\gamma_2^2-1)m_2^2 $ from conservation of momentum. …
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