Consider fields $\rho \left( \vec{r} \right)$, $\vec{J} \left( \vec{r} \right)$, $\vec{E} \left( \vec{r} \right)$ and $\vec{B} \left( \vec{r} \right)$ in $\mathbb{R}^3$, with their usual meaning as per Electrodynamics. 

Take any finite volume $V_s$ outside of which $\vec{J}\left(\vec{r}\right)$ and $\rho\left(\vec{r}\right)$ are $0$. Then, we know that $\vec{E}\left(\vec{r}\right) $ and $\vec{B}\left(\vec{r}\right) $ for any $\vec{r}$ are as follows:

$$
\vec{E} \left( \vec{r} \right) = 
   \frac{1}{4\pi \epsilon_0}
      \iiint_{V_s} 
          \frac{\rho\left(\vec{r}_s\right)}{\left|\vec{r}-\vec{r}_s\right|^3} 
          \left(\vec{r}-\vec{r}_s\right)
      \space dV\left(\vec{r}_s\right)
$$
$$
\vec{B} \left( \vec{r} \right) = 
   \frac{\mu_0}{4\pi}
      \iiint_{V_s} 
          \frac{\vec{J}\left(\vec{r}_s\right)}{\left|\vec{r}-\vec{r}_s\right|^3} 
          \times \left(\vec{r}-\vec{r}_s\right) 
      \space dV\left(\vec{r}_s\right)
$$
Now my question is, is it possible to _mathematically_ prove that the following surface integral will always evaluate to zero? If so, what is the proof? (To clarify, $\partial V_s$ is the bounding surface of the volume $V_s$ mentioned earlier)

$$
\frac{1}{\mu_0} \oint_{\partial V_s} \left(\vec{E}\left(\vec{r}\right) \times \vec{B}\left(\vec{r}\right)\right)\cdot d\vec{S}\left(\vec{r}\right)
$$
Motivation: I'm looking for proof that time invariant sources (static charges and constant currents confined to a volume) cannot radiate any energy, and I'm trying to do that without invoking the Hertzian dipole and Fourier analysis.

Thanks...

**Update**

As pointed out below, since $\vec{E}$ and $\vec{B}$ are time invariant, applying Poynting's theorem this boils down to proving that the following volume integral is zero:
$$
- \iiint_{V_s}
      \left(       
        \vec{J}\left(\vec{r}\right)
        \cdot
        \vec{E}\left(\vec{r}\right)
      \right)     
   \space dV\left(\vec{r}\right)
$$
So can *this* be proved, given that $\vec{J}$, $\vec{E}$, $\vec{B}$ and $\rho$ are all time invariant?

Thanks...