Let's assume that an object has KE expressed by velocity $v$ and mass $m$. 
If work $w$ has been done to this object such that its new speed (same direction) is $s$. There are 2 ways(I know) to calculate $w$. The first is 
$ \frac {1}{2} ms^2 -  \frac {1}{2} mv^2$. The other way is (assuming you know distance and acceleration) to use $w=mda $
then
$d= \frac {1}{2}at^2 + vt  $ 


$\frac{2d}{a}= t^2 + \frac {2v}{a}t$

$\frac {2d}{a} +\frac {v^2}{a^2} = t^2 + \frac {2v}{a}t + \frac {v^2}{a^2}$ 


$\frac {2d}{a} +\frac {v^2}{a^2} = (t+\frac {v}{a})^2$


$\sqrt {\frac {2d}{a} +\frac {v^2}{a^2}} = t + \frac{v}{a}$ 


$\sqrt {\frac {2da+v^2}{a^2}}= t + \frac{v}{a}$


$\frac {\sqrt {2da+v^2}}{a} = t + \frac{v}{a}$ 


$\frac {\sqrt {2da+v^2}-v}{a} = t $ 


and  the speed is a*t which is equal to 


${\sqrt {2da+v^2}-v}$


remember that 


$ da = \frac {w}{m}$


$ s = \sqrt {\frac {2w}{m}+v^2}-v$


$ (s+v)^2 = \frac{2w}{m} +v^2$

$ \frac{1}{2}m((s+v)^2-v^2) = w $


simplify and it will be


$ w= \frac {1}{2} ms^2 + \frac{1}{2} mvs$


which isn't quite the other formula. Why is it that my formula doesn't work?