When light is incident at object. The light can either be absorbed, speculary reflected, or scattered.
A green object, Absorbs all light apart from green, and then scatters green light in all directions.
This green light then travels to my eye, and my brain processes it as a "green object".
The light scattered from the green object that does not travel towards me, does not get registered by my brain, and therefore I will not see those rays.
I hope everything upto this point is clear.
You talk about "mixing light rays" and then draw a diagram of those rays and then I presume you think that we see those rays? We do not.
We do not see light that doesn't directly travel from the source to the eye in straight lines.
Light rays do not interact with eachother.
The reason that the "entire room" is lit up, is because the rays that do not directly enter our eye, are incident on something like a wall.
The rays from that green object that miss our eyes, instead reach the Wall, get absorbed and remitted by the molecules the wall.
The light from the wall gets scattered in all directions, the rays from the wall that don't travel directly to our eye We don't see. The rays from the wall that DO travel directly to our eyes, we do see.
The light from the wall is registered by our brains as what ever colour the wall happens to be.
Ofcourse the light directly from the torch ALSO gets directly scattered by the wall aswell (along with the light scattered off the green object)
This is also a reason why if you put a green object close to a wall, the wall appears slightly greener. The light from the green object is scattered by the wall, so that our brains register the wall having a greener tint to it. As there is more greenlight that is now scattered, in addition to the variety of light scattered by the torch.