When we talk about radiation, we often talk about the near and far field radiation. For the near field, the Poynting vector falls off like 1/r^3 and the far field Poynting vector falls off like 1/r^2. Once the distance gets big, the far field term dominates, hence the name. Now, it is the far field term that is associated with the EM radiation emitted by a particle. Since the area of a sphere increases like r^2, the far field power emitted by the particle (the integral of the Poynting vector over the area of the sphere) is constant. My question is if the near field also has such a power (integral of Poynting over the area of a sphere) associated with it, or if the various Poynting vectors nicely cancel out as to make the total power zero (if that's the case, then I'd love a proof that it's 0). I know that the far field dominates over large distances, but if the near field also has such a power associated with it, then the total power must change with distance, which would seem to break energy conservation. And if the near field also has a power and it somehow doesn't break energy conservation, then why is it only the far field power that is associated with the energy emitted by the particle?