This was a problem in our physics final exam and I still haven't figured it out completely.
A long non-conductive cylindrical shell with inner radius "a" and outer radius "b" is surrounded by another cylindrical shell with inner radius "c" and outer radius "d" such that a<b<c<d. The inner shell has a charge density of $$\rho=-Br $$ and the outer shell has a density of $$\rho=Ar.$$
$$(A, B>0)$$

Consider infinity to have zero potential.

find the Electric potential where:

a) r>d

b) c<r<d

c)   a<r<b

d) r<a 

e) find the ratio of A to B such that Electric Potential would be zero in the region where r>d.





for part a, I tried to solve it in this way(I don't know if it
s correct). We can find the electric field in this region using gauss's law:
$$E_5=\frac {1}{3\epsilon_0 r}A(d^3-c^3)-B(d^3-a^3)$$
and then considering P as a point located in this region(r>d) with distance r from the center:
$$V_p-V_\infty = +\int_{\infty}^r E_5.dr  $$
And I get stuck in this part, where the right-hand integral is undefined. I don't know whether I'm making a mistake somewhere or there's something wrong with the question. 




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