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mike stone
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I think the term gluon condensate" usually means $<F_{\mu\nu} F^{\mu\nu}/4>$. This is not really a condensate however, because it does not break any symmetry. Furthermore, since the operator $F_{\mu\nu} F^{\mu\nu}$ mixes with the identity operator under renormalization, it is a non-universal quantity, so it is not clear what it means physically.

mike stone
  • 56.5k
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  • 148