At low frequency, the capacitor acts as an open circuit. This leaves you with an opamp with just two resistors for which you can compute the gain as -10.

At very high frequency, the capacitor acts as a short circuit. At this point the output of the amplifier is connected to the inverting input; with the inverting input at "virtual ground", there will be no gain.

In the general case, the gain is the ratio of the impedance of the feedback network over the feed-in network. The feedback network comprises of a parallel circuit of a resistor and a capacitor; the feed-in network in this case is just a single resistor. It follows that

$$G = \frac{\frac{R_2}{1+j\omega R_2 C}}{R_1}$$

It is easy to see that when $\omega \rightarrow 0$, this reduces to the results I gave above.