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T-Duality for closed bosonic string: what is the difference between a graviphoton and a B-vector?

Consider the closed bosonic string in 26 dimensions, of which one physical dimension, say $X^{24}$ is compactified into a circle of radius $R$. The lowest lying massless states are the graviton, the antisymmetric $B_{\mu\nu}$ field, the dilaton $\phi$, and two ``vectors'', the so called graviphoton and B-vector. They are described by

$\alpha^{i}_{-1} \tilde{\alpha}^{24}_{-1}|p\rangle = 0$ and $\alpha^{24}_{-1}\tilde{\alpha}^{i}_{-1}|p\rangle$, with $p^2 = 0$.

What is the difference between these two states? I see that they are defined differently, but the only difference is in which (antiholomorphic) creation operator appears first.

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