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Physical interpretation and validity of QHO hamiltonian term: $\hat{a}\hat{n} + \hat{n}\hat{a}^{\dagger}$ [closed]

For a quantum harmonic oscillator can we have a Hamiltonian term of the following form, and what would be its physical interpretation: $$\hat{a}\hat{n} + \hat{n}\hat{a}^{\dagger}$$
Mohit Kumar's user avatar
10 votes
3 answers
1k views

Quantum harmonic oscillator meaning

Imagine we want to solve the equations $$ i \hbar \frac{\partial}{\partial t} \left| \Psi \right> = \hat{H}\left| \Psi \right> $$ where $$\hat{H} = -\frac{\hbar^2}{2m} \frac{\partial^2}{\partial ...
Jorge's user avatar
  • 221
0 votes
1 answer
36 views

The time-derivative of the Hamiltonian for a 1D harmonic potential [closed]

I do not understand how to take the time derivative of the following Hamiltonian $\hat{H}(t) = \frac{\hat{p}^2}{2m} + \frac{1}{2}m\omega^2(\hat{x}-a(t))^2$, where $a(t) = v_0t$. For instance how does ...
Rillard's user avatar
5 votes
1 answer
234 views

Motivation for introducing ladder operators for the simple harmonic oscillator in quantum mechanics

I am teaching a quantum mechanics course and I have to explain the simple harmonic oscillator. I am familiar with the introduction of ladder operators and the consecutive proofs that show that we can ...
P. C. Spaniel's user avatar
1 vote
3 answers
280 views

It seems that expectation value of $H$ on coherent states is independent of time? But why?

Let's say the particle is in the state $| \psi(0) \rangle = \exp(-i\alpha p/\hbar) |0 \rangle$, where $p$ is the momentum operator. I have to show that $| \psi(0) \rangle$ is a coherent state and to ...
Damark's user avatar
  • 91
3 votes
0 answers
169 views

Quantum Harmonic Oscillator: find a constant $\beta$ such that $U=\exp(\beta a^{\dagger} - \beta^*a)$ diagonalize $H$ [closed]

Given Hamiltonian of Quantum Harmonic Oscillator, $$H = \frac{p^2}{2m}+\frac{1}{2}m\omega^2 x^2-\gamma x$$ I have to find a constant $\beta$ such that the unitary operator $U=\exp(\beta a^{\dagger} - \...
Damark's user avatar
  • 91
4 votes
1 answer
215 views

What is the probability to find the system in the ground state? [closed]

I previously posted a question related to this Hamiltonian, but the original concern was different: We examine the following Hamiltonian: \begin{equation} H = \frac{p^2}{2m} + \frac{1}{2}m\omega^2x^2 -...
user avatar
3 votes
2 answers
372 views

Does the state change, when the Hamiltonian changes?

Consider the Hamiltonian \begin{equation} H = \frac{p^{2}}{2m} + \frac{1}{2} m\omega^{2}x^{2} - \theta(t) qEx \end{equation} where $\theta(t)$ is $0$ for $t = 0$ and $1$ for $t > 0$. If at $t = ...
user avatar
0 votes
2 answers
145 views

Quantum harmonic oscillator as the potential becomes zero

I'm having a question concerning the quantum harmonic oscillator: If, for instance, $\omega\to 0$ the Hamiltonian $$ \hat{H} = \frac{\hat{p}^2}{2m} + \frac{1}{2}m\omega^2 x^2\tag{1} $$ becomes that of ...
astro-dk's user avatar
0 votes
1 answer
255 views

How to diagonalize a single particle hamiltonian? [closed]

$$H=\hbar\omega \left(a^\dagger a+\frac{1}{2}\right)+\hbar \omega_0\left(a^\dagger+a\right)$$ How to diagonalize $H$ and find its eigenenergies?
Sophie's user avatar
  • 11
4 votes
1 answer
119 views

Interpretation of this Hamiltonian

I'm studying a system with the following Hamiltonian $$ H = \frac{1}{2}P^TAP + \frac{1}{2}Q^T B Q$$ where $P,Q$ are canonical variables (4-vectors) and $A,B$ matrices such that $A = A^\dagger$ and $B =...
Gyro's user avatar
  • 173
1 vote
3 answers
115 views

What is the form of an electrical oscillator Hamiltonian?

I found this https://en.wikipedia.org/wiki/Harmonic_oscillator in my search results when I search for "electrical oscillator Hamiltonian" and some other things too. But none of them answer ...
Tachyon's user avatar
  • 2,042
1 vote
1 answer
55 views

Eigenstates for quantized oscillator [closed]

Hi I am new to solid state physics and am reviewing a prior knowledge section and would like some clarification. The following appeared in the course notes: From my understanding, Eigenstates are ...
Harry J Critchfield's user avatar
1 vote
0 answers
65 views

Using variation principle on quantum oscillator with general potential

Consider a general bounding potential $V(x)$. The hamiltonian is $$H = \frac{p^2}{2m} + V(x).$$ We want to apply the variation principle in equation $$F\leq F_0+\langle H-H_0\rangle_0.$$ $\langle\...
Dio's user avatar
  • 333
-2 votes
1 answer
174 views

Why the first-order derivative is missing when composing a Hamiltonian of simple harmonic oscillator by the lowering and the raising operators? [closed]

Given the lowering operator ($a$) and the raising operator ($a^\dagger$) $$\begin{align*} a &= \frac{1}{\sqrt{2m \hbar \omega}}\left(-i \hbar \frac{\partial}{\partial x} - i m \omega x\right) \\ a^...
IvanaGyro's user avatar
  • 277
2 votes
0 answers
40 views

Propagator for radial force field?

The propagator $K(x,y;t)$ is well known for the (1D) harmonic oscillator: $$H = -\frac{\hbar^2}{2m}\frac{\partial^2}{\partial x^2} + \frac{m}{2}\omega^2 x^2$$ is there a simple closed form solution ...
user avatar
1 vote
0 answers
110 views

Canonical transformation of the harmonic oscillator‘s Hamiltonian [closed]

I could deduce the Hamiltonian of the damped harmonic oscillator: $$ H=\frac{p^2}{2m}e^{-2 \gamma t}+\frac{m \omega_0^2 q^2}{2}e^{2 \gamma t} $$ Using the canonical transformation $Q=e^{\gamma t}q, P=...
Henry T.'s user avatar
  • 522
3 votes
1 answer
324 views

Modified quantum harmonic oscillator spectrum and eigenstates

I am trying to find the eigenstates/eigenvalues of the following Hamiltonian $$ \hat{H} = \hbar \omega \Big(\hat{a}^{\dagger}\hat{a}+\frac{1}{2}\Big)+A\big(\hat{a}^{\dagger}\hat{a}^{\dagger}+\hat{a}\...
Andrea's user avatar
  • 745
1 vote
0 answers
43 views

I'm getting the wrong Hamiltonian of the quantum oscillator

First, I generalised the oscillator's Hamilton's equations to complex variables: $$\frac{dz_1}{dt}=\frac{\partial (z_1^2+z_2^2)}{\partial z_1}=2z_1$$ $$\frac{dz_2}{dt}=2z_2$$ So the real world ...
Egg Man's user avatar
  • 959
0 votes
1 answer
87 views

Eigenstates harmonic oscillator with mass matrix

Consider the 2D harmonic oscillator $H = \langle \nabla, M\nabla \rangle+ \vert x \vert^2$ where $x \in \mathbb R^2$ and $M$ is a symmetric mass matrix with strictly positive eigenvalues. Is it known ...
Guido's user avatar
  • 101
0 votes
2 answers
250 views

Time Derivative of the Hamiltonian for a Quantum Simple Harmonic Oscillator

I am reading an article on quantum refrigerator. Here is the link of the article. The arXiv version is available here. The working medium is an ensemble of non-interacting particles in a harmonic ...
Ali Pedram's user avatar
1 vote
2 answers
4k views

Hamiltonian of two coupled oscillators

Lets say I have this system: Two different masses with three different springs. It's not very nice to do, but I can find the eigenvalues of this system (It's not nice because the two masses are ...
Eliahu's user avatar
  • 11
1 vote
2 answers
616 views

Confusion in Quantum Harmonic Oscillator

I am confused with the meaning of the particle number of a quantum harmonic oscillator. Classically, the Hamiltonian of harmonic oscillator in phase space is defined as follows: $$H = \frac{p^{2}}{2m} ...
Ricky Pang's user avatar
1 vote
3 answers
96 views

Why is $\langle n| (\hat{a}+\hat{a}^{\dagger})^2|n\rangle=2n+1$ for the QM harmonic oscillator? [closed]

Consider a one-dimensional quantum-mechanical simple harmonic oscillator of mass $m$ and potential energy $\frac{kx^2}{2}$. The energy levels of this system are $E_n=(n+\frac{1}{2})\hbar\omega $ for $...
test123's user avatar
  • 239
1 vote
1 answer
440 views

Statistical weight for $N$ harmonic oscillators in microcanonical ensemble

I would like to compute the statistical weight for the microcanonical ensemble for $N$ harmonic oscillators. To do that i use the hamiltonian of the harmonic oszillator: $$H(q,p)=\sum\limits_{i=1}^N \...
StefanBoltzmann's user avatar
0 votes
0 answers
19 views

Transmon: why do we need unharmonic hamiltonian to isolate energy levels? [duplicate]

With a quantum harmonic oscillator, we cannot isolate energy levels, e.g. to create a qubit. We need to embed anharmonicity, to get unevenly-spaced energy levels and so making them distinguishable. ...
Daniele Cuomo's user avatar
7 votes
5 answers
1k views

How can zero-point energy have any measurable effect when it is just a constant offset to the Hamiltonian?

In classical (say Hamiltonian) mechanics, adding a constant energy offset has no effect on the dynamics of the physical system. One way to understand this might be to understand that Hamilton's ...
Jagerber48's user avatar
  • 15.2k
3 votes
1 answer
158 views

Peskin and Schroeder, where is the mass in the denominator of the simple harmonic oscillator Hamiltonian?

This relates to page 20 of Peskin and Schroeder. They state that the Fourier transform of the Klein-Gordon field satisfies the following: $$\left[\frac{\partial^2}{\partial t^2}+(|\vec p|^2+m^2)\right]...
Charlie's user avatar
  • 7,008
0 votes
2 answers
2k views

Deriving the Hamiltonian for a simple pendulum using mechanical momentum as a free parameter

So when we covered the derivation of a simple pendulum we , and from what ive found on the web, defined our free parameter as $q=L\theta$ and arrive at the Hamiltonian for a Harmonic oscillator. But ...
Notan's user avatar
  • 25
2 votes
1 answer
246 views

How to determine the ground state of quantum harmonic oscillator like Hamiltonian?

For the time-dependent Hamiltonian $$H = \frac{\hat{P}^2}{2m} + \frac{1}{2} m\omega^2\hat{X}^2 + m\omega^2vt\hat{X} +v\hat{P}$$ I would like to calculate the ground state, more precise, the stationary ...
gamma's user avatar
  • 447
2 votes
1 answer
939 views

Interpreting Hamiltonian of single-mode squeezing

Hamiltonian represents energy. I can understand this when considering about harmonic oscillator, whose Hamiltonian is expressed as: $$ \hat{H} = \frac{1}{2m}\hat{p}^2 + \frac{m\omega^2}{2}\hat{q}^2$$ ...
ytaguchi's user avatar
0 votes
2 answers
704 views

Is symmetrization $xp-px$ required for commutation $[H,x]=0$?

Given a Quantum Hamiltonian: $$\hat{H}=ax^2+bp^2$$ It does not commute with either $x$ or $p$. Suppose we have a Hamiltonian :$$H = k \hat{p}\hat{x}$$ why do we need it to be: $$H = k (\hat{p}\hat{x} -...
Qbuoy's user avatar
  • 11
1 vote
0 answers
20 views

In context of defining a hamiltonian of a system, can someone please explain the meaning of zero-point oscillations/vibrations?

I came across this term while studying electron delocalization in amorphous semiconductors. The delocalization of the electronics wavefunction is explained in terms of zero-point oscillations.
Rishi Shivhare's user avatar
0 votes
1 answer
408 views

Calculating exact energy levels of perturbed Hamiltonian

I wish to find the exact energy levels of the following perturbed hamiltonian. $$\hat{H}=\frac{p^2}{2m}+\frac{m\omega^2}{2}x^2+\alpha x+\beta p^2.$$ I believe that it can be solved by using the ...
Nick Heumann's user avatar
0 votes
0 answers
401 views

Solution to two non-coupled quantum harmonic oscillators

Given the following Hamiltonian: $$\hat H = -\frac{\hbar^2}{2m}\frac{\partial^2}{\partial x_1^2} -\frac{\hbar^2}{2m}\frac{\partial^2}{\partial x_2^2} + \frac{1}{2}m\omega_1^2x_1^2 + \frac{1}{2}m\...
Tapedeck's user avatar
0 votes
1 answer
51 views

Why do we consider only one mass when solving linear harmonic oscillators in quantum physics?

While solving the Hamiltonian, books concentrate on the horizontal flow with only one mass attached to the string. Isn't there any consequences if we add more masses and why is friction always ignored?...
kaziba stephen's user avatar
-2 votes
2 answers
435 views

Is a quantum harmonic oscillator always infinite dimensional?

Let us assume we have a quantum particle in a harmonic potential with the Hamiltonian $$H = \sum_n n \omega |n\rangle\langle n|$$ If I am not mistaken. Now when talking about harmonic oscillators ...
CatoMaths's user avatar
  • 415
1 vote
4 answers
192 views

Why we neglect the $\hbar ω/2$ in the Hamiltonian of the the Electromagnetic Field?

After the quantization of the electric and the magnetic field, we get the Hamiltonian of the electromagnetic field: $$H= \hbar ω(a^{\dagger}a +1/2) .$$ with $\hbar$ the planck constant and $a^{\...
Qninja's user avatar
  • 53
0 votes
1 answer
291 views

Harmonic oscillator energy difference between $(n+\frac{1}{2})h \omega$ and $(n+\frac{1}{2})\hbar \omega$

When I was studying the Harmonic Oscillator using the Schrödinger equation, I was told in lectures to pay attention to the units. There were 2 different equations given for the Energy of a Harmonic ...
David Smith's user avatar
4 votes
3 answers
4k views

What is the Hamiltonian in the "energy basis" for a simple harmonic oscillator?

My textbook says that for a simple harmonic oscillator the Hamiltonian can be expressed in the "energy basis" in this way: $$\hat H=\hbar\omega\bigg(\hat a^{\dagger}\hat a + {1\over 2}\bigg).$$ I ...
matryoshka's user avatar
0 votes
1 answer
345 views

Eigenfunctions of Hamiltonian (question about the book "Quantum Field Theory for the Gifted Amateur")

In the book "Quantum Field Theory for the Gifted Amateur" by Blundell and Lancaster, (page 21) the Hamiltonian (when discussing the number operator) is given by $$ \hat{H} = \left(\hat{a}^{\dagger}\...
Jack G's user avatar
  • 41
1 vote
0 answers
360 views

One Hamilton Operator for two independent harmonic oscillators

If we consider two independent harmonic oscillators (identical too a two dimensional harmonic oscillator), the hamilton operator is $$ H = \frac{p_1^2}{2m_1}+\frac{1}{2}m_1\omega_1^2x_1^2 + \frac{...
seven_'s user avatar
  • 11
2 votes
1 answer
2k views

Systematic way of decoupling a coupled oscillators Hamiltonian

I have been faced with the Hamiltonian $$H = P_1^2/2m_1 + P_2^2/2m_2 + (k/2) x_1^2 + (k/2)x_2^2 + (K/2)(x_1-x_2)^2$$ I'm trying to find a systematic way to decouple it other than guessing. So, I wrote ...
Ammar Amgad's user avatar
2 votes
1 answer
2k views

Transforming simple Hamiltonian to interaction picture

I am trying to follow the math in a paper, and in it they do a lot of transforming into the interaction frame. It has been awhile since I have done these kind of calculations explicitly by hand and I ...
user41178's user avatar
  • 1,001
-1 votes
2 answers
1k views

Hamiltonian approximation of the Coulomb interaction energy of two charged oscillators

I'm adding an excerpt from the book Introduction to Solid State Physics 7th edition by Charles Kittel. I don't see how they arrived at the approximation of the Hamiltonian (2) by expanding it. If $...
Mark A. Ruiz's user avatar
1 vote
2 answers
1k views

Hamiltonian of Klein-Gordon Field

The Hamiltonian of the Klein-Gordon Field may be written $$H=\int\frac{d^{3}p}{(2\pi)^{3}}\frac{1}{2\omega_{\mathbf{p}}}\omega_{\mathbf{p}}\left(a^{\dagger}(p)a(p)+\frac{1}{2}(2\pi)^{3}2\omega_{\...
klgklm's user avatar
  • 411
2 votes
4 answers
3k views

Recovering the Hamiltonian from ladder operators

The Hamiltonian for the quantum harmonic oscillator is $$\hat{H}=-\dfrac{\hbar^2}{2m}\dfrac{\partial^2}{\partial x^2}+\dfrac{1}{2}m\omega^2 x^2$$ and one can try to factorise it by writing down what ...
Demosthene's user avatar
  • 1,389
1 vote
2 answers
473 views

Harmonic oscillator hamiltonian (QFT)

I have a little doubt about the harmonic oscillator hamiltonian written at the beginning of Peskin & Schroeder's "An introduction to quantum field theory"; I enclose the picture of the page. ...
PsycoPulcino's user avatar
-2 votes
1 answer
241 views

Canonical Quantization of harmonic oscillator

I have a system of two particles with the usual Lagrangian, $$L=\frac12M_1{\dot{x_1}}^2+\frac12M_2{\dot{x_2}}^2-\frac12k({x_1}^2+{x_2}^2)$$ I want to find the quantum Hamiltonian of the system. I ...
danula godagama's user avatar
3 votes
1 answer
441 views

What is meant by taking the partial derivative of the Hamiltonian in this situation?

I'm doing a computation involving the quantum mechanical harmonic oscillator, and I have an expression of the form $\frac{\partial}{\partial \omega} \hat{H}$ where $$\hat{H} = \frac{1}{2m} \left( - \...
FlagCapper's user avatar