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110 votes
7 answers
134k views

What do spacelike, timelike and lightlike spacetime interval really mean?

Suppose we have two events $(x_1,y_1,z_1,t_1)$ and $(x_2,y_2,z_2,t_2)$. Then we can define $$\Delta s^2 = -(c\Delta t)^2 + \Delta x^2 + \Delta y^2 + \Delta z^2,$$ which is called the spacetime ...
Gold's user avatar
  • 37.4k
107 votes
4 answers
11k views

Why does nature favour the Laplacian?

The three-dimensional Laplacian can be defined as $$\nabla^2=\frac{\partial^2}{\partial x^2}+\frac{\partial^2}{\partial y^2}+\frac{\partial^2}{\partial z^2}.$$ Expressed in spherical coordinates, it ...
Sam Jaques's user avatar
  • 1,357
104 votes
2 answers
8k views

Is there such thing as imaginary time dilation?

When I was doing research on General Relativity, I found Einstein's equation for Gravitational Time Dilation. I discovered that when you plugged in a large enough value for $M$ (around $10^{19}$ ...
John Dumancic's user avatar
73 votes
2 answers
9k views

Is spacetime flat inside a spherical shell?

In a perfectly symmetrical spherical hollow shell, there is a null net gravitational force according to Newton, since in his theory the force is exactly inversely proportional to the square of the ...
Leos Ondra's user avatar
  • 2,193
71 votes
5 answers
24k views

Conformal transformation/ Weyl scaling are they two different things? Confused!

I see that the weyl transformation is $g_{ab} \to \Omega(x)g_{ab}$ under which Ricci scalar is not invariant. I am a bit puzzled when conformal transformation is defined as those coordinate ...
vishmay's user avatar
  • 1,126
65 votes
4 answers
14k views

Lie derivative vs. covariant derivative in the context of Killing vectors

Let me start by saying that I understand the definitions of the Lie and covariant derivatives, and their fundamental differences (at least I think I do). However, when learning about Killing vectors I ...
Javier's user avatar
  • 28.6k
59 votes
11 answers
14k views

Is spacetime wholly a mathematical construct and not a real thing? [closed]

Speaking of what I understood, spacetime is three dimensions of space and one of time. Now, if we look at general relativity, spacetime is generally reckoned as a 'fabric'. So my question is, whether ...
OmG's user avatar
  • 649
42 votes
4 answers
8k views

How do we know that gravity is spacetime and not a field on spacetime?

How do we know that gravity is the curvature of spacetime as opposed to a field, which couples equally to all objects, on spacetime?
Luke's user avatar
  • 2,310
39 votes
5 answers
47k views

Why is the covariant derivative of the metric tensor zero?

I've consulted several books for the explanation of why $$\nabla _{\mu}g_{\alpha \beta} = 0,$$ and hence derive the relation between metric tensor and affine connection $\Gamma ^{\sigma}_{\mu \beta}...
Aftnix's user avatar
  • 929
38 votes
8 answers
5k views

Interval preserving transformations are linear in special relativity

In almost all proofs I've seen of the Lorentz transformations one starts on the assumption that the required transformations are linear. I'm wondering if there is a way to prove the linearity: Prove ...
a06e's user avatar
  • 3,802
35 votes
4 answers
8k views

How can we recover the Newtonian gravitational potential from the metric of general relativity?

The Newtonian description of gravity can be formulated in terms of a potential function $\phi$ whose partial derivatives give the acceleration: $$\frac{d^2\vec{x}}{dt^2}=\vec{g}=-\vec{\nabla}\phi(x)=\...
Beyond-formulas's user avatar
35 votes
2 answers
5k views

Why isn't the GPS location calculated from the Schwarzschild metric?

The GPS uses the flat space light propagation formula to calculate the distance from the source (the satellite) to the receiver (observer on Earth): $$ d=c \cdot \Delta t$$ where $c$ is the speed of ...
label's user avatar
  • 535
34 votes
11 answers
12k views

Is the "spacetime" the same thing as the mathematical 4th dimension?

Is the "spacetime" the same thing as the mathematical 4th dimension? We often say that time is the fourth dimension, but I am wondering if it's means that time is like the fourth geometrical axis, or ...
jojafett's user avatar
33 votes
5 answers
4k views

Can Lagrangian be thought of as a metric?

My question is, can the (classical) Lagrangian be thought of as a metric? That is, is there a meaningful sense in which we can think of the least-action path from the initial to the final ...
N. Virgo's user avatar
  • 34.9k
32 votes
3 answers
10k views

Can quaternion math be used to model spacetime?

Quaternions are commonly used to model 4 dimensional systems where the quaternion consists of a real 3 dimensional vector and an imaginary scalar. So on the surface Quaternions seem well suited to ...
docscience's user avatar
  • 11.7k
32 votes
4 answers
4k views

Can general relativity be completely described as a field in a flat space?

Can general relativity be completely described as a field in a flat space? Can it be done already now or requires advances in quantum gravity?
Anixx's user avatar
  • 11.3k
28 votes
4 answers
4k views

How do we know the Schwarzschild solution contains an object of mass $M$?

The Schwarzschild metric is $$ds^2 = - \left( 1 - \frac{2GM}{r} \right) dt^2 + \left(1-\frac{2GM}{r}\right)^{-1} dr^2 + r^2 d\Omega^2.$$ In all GR books, it is stated that $M$ is the mass of the black ...
knzhou's user avatar
  • 105k
27 votes
4 answers
6k views

Are black holes perfect spheroids?

What I know about black holes (correct me if I'm wrong) is that they are the most compact objects in the universe that have been discovered. Due to all that gravity, wouldn't black holes be a perfect ...
Axis Omega's user avatar
26 votes
7 answers
8k views

Why do we select the metric tensor for raising and lowering indices?

Any rank 2 tensor would do the same trick, right? Then, which is the motivation for choosing the metric one? Also, if you help me to prove that $g^{kp}g_{ip}=\delta^k_i$, I would be thankful too ^^...
Stefano's user avatar
  • 653
26 votes
9 answers
5k views

Time is the only dimension that has an arrow, and the only dimension which contributes an opposite sign to the metric. Is that just a coincidence?

Time is different from space in these two seemingly independent ways. One of them is generally believed to have to do with special boundary conditions at the beginning of time. But if you knew nothing ...
reductionista's user avatar
25 votes
5 answers
8k views

Why do we need tensors in modern physics?

I am wondering why do we really need the concept of tensor. I think it is like vectors, just as a notation of a set of related parameters. I could write the Navier–Stokes equations with scalars, or ...
Jack's user avatar
  • 47
25 votes
2 answers
15k views

Lorentz invariance of the Minkowski metric

As far as I understand, one requires that in order for the scalar product between two vectors to be invariant under Lorentz transformations $x^{\mu}\rightarrow x^{\mu^{'}}=\Lambda^{\mu^{'}}_{\,\,\...
Will's user avatar
  • 3,093
25 votes
2 answers
8k views

How does the Hubble parameter change with the age of the universe?

How does the Hubble parameter change with the age of the universe? This question was posted recently, and I had almost finished writing an answer when the question was deleted. Since it's a shame to ...
John Rennie's user avatar
24 votes
5 answers
15k views

How do I calculate the perturbations to the metric determinant?

I am trying to calculate $\sqrt{-g}$ in terms of a background metric and metric perturbations, to second order in the perturbations. I know how to expand tensors that depend on the metric, but I don't ...
david's user avatar
  • 541
24 votes
4 answers
14k views

Why is the covariant derivative of the determinant of the metric zero?

This question, metric determinant and its partial and covariant derivative, seems to indicate $$\nabla_a \sqrt{g}=0.$$ Why is this the case? I've always learned that $$\nabla_a f= \partial_a f,$$ ...
Hans Schmuber's user avatar
24 votes
1 answer
2k views

Causality and how it fits in with relativity

I was talking to my teacher the other day about Einstein's spacetime and there's one thing he couldn't explain about the nature of Cause. I may be being stupid or just unable to comprehend, thanks for ...
Oliver Cohen's user avatar
23 votes
5 answers
3k views

Curvature of Hilbert space

That may appear as a dumb question, but: Does Hilbert space have curvature, or is it a flat space? How and why?
Les Adieux's user avatar
  • 3,735
22 votes
9 answers
11k views

Minkowski Metric Signature

When I learned about the Minkowski Space and it's coordinates, it was explained such that the metric turns out to be $$ ds^{2} = -(c^{2}dx^{0})^{2} +(dx^{1})^{2} + (dx^{2})^{2} + (dx^{3})^{2} $$ ...
Doryan Miller's user avatar
22 votes
5 answers
8k views

Inverse and Transpose of Lorentz Transformation

I've seen this question asked a few times on Stack Exchange, but I'm still quite confused why the following "contradiction" seems to arise. By definition: $(\Lambda^T)^{\mu}{}_{\nu} = \...
Shrey's user avatar
  • 736
22 votes
3 answers
9k views

What is meant when it is said that the universe is homogeneous and isotropic?

It is sometimes said that the universe is homogeneous and isotropic. What is meant by each of these descriptions? Are they mutually exclusive, or does one require the other? And what implications rise ...
voithos's user avatar
  • 3,439
22 votes
6 answers
4k views

Interpretation of a singular metric

I'm interested to find out if we can say anything useful about spacetime at the singularity in the FLRW metric that occurs at $t = 0$. If I understand correctly, the FLRW spacetime is a combination ...
John Rennie's user avatar
22 votes
2 answers
8k views

How do I derive the Lorentz contraction from the invariant interval?

While reviewing some basic special relativity, I stumbled upon this problem: From the definition of the proper time: $$c^2d\tau^2=c^2dt^2-dx^2$$ I was able to derive the time dilation formula by using ...
Danu's user avatar
  • 16.5k
22 votes
5 answers
16k views

How to prove that orthochronous Lorentz transformations $O^+(1,3)$ form a group?

Orthochronous Lorentz transform are Lorentz transforms that satisfy the conditions (sign convention of Minkowskian metric $+---$) $$ \Lambda^0{}_0 \geq +1.$$ How to prove they form a subgroup of ...
Siyuan Ren's user avatar
  • 5,042
21 votes
3 answers
4k views

Why is spacetime not Riemannian?

I apologize if this is a naïve question. I'm a mathematician with, essentially, no upper-level physics knowledge. From the little I've read, it seems that spacetime is Lorentzian. Unfortunately, the ...
Robin Goodfellow's user avatar
21 votes
2 answers
10k views

Covariant vs contravariant vectors

I understand that, in curvilinear coordinates, one can define a covariant basis and a contravariant basis. It seems to me that any vector can be decomposed in either of those basis, thus one can have ...
Botond's user avatar
  • 1,016
21 votes
4 answers
2k views

Difference between matrix representations of tensors and $\delta^{i}_{j}$ and $\delta_{ij}$?

My question basically is, is Kronecker delta $\delta_{ij}$ or $\delta^{i}_{j}$. Many tensor calculus books (including the one which I use) state it to be the latter, whereas I have also read many ...
GRrocks's user avatar
  • 2,778
20 votes
9 answers
6k views

Quaternions and 4-vectors

I recently realised that quaternions could be used to write intervals or norms of vectors in special relativity: $$(t,ix,jy,kz)^2 = t^2 + (ix)^2 + (jy)^2 + (kz)^2 = t^2 - x^2 - y^2 - z^2$$ Is it ...
Isaac's user avatar
  • 2,930
20 votes
3 answers
22k views

D'Alembertian for a scalar field

I have read that the D'Alembertian for a scalar field is $$ \Box = g^{\nu\mu}\nabla_\nu\nabla_\mu = \frac{1}{\sqrt{-g}}\partial_\mu (\sqrt{-g}\partial^\mu). $$ Exactly when is this correct? Only for $...
innisfree's user avatar
  • 15.3k
20 votes
1 answer
8k views

What do the off-diagonal elements of the metric tensor represent?

For certain metrics in general relativity, the metric tensor $g_{{\alpha}{\beta}}$ is not a diagonal matrix. For example, the Alcubierre metric is given by $$ds^2 = -dt^2 + [dx - V_s(t) f(r_s) dt]^2 +...
Wise Owl's user avatar
  • 493
19 votes
5 answers
2k views

Where is the Lorentz signature enforced in general relativity?

I'm trying to understand general relativity. Where in the field equations is it enforced that the metric will take on the (+---) form in some basis at each point? Some thoughts I've had: It's baked ...
Zinklestoff's user avatar
19 votes
2 answers
2k views

How can one obtain the metric tensor numerically?

I am self-studying General Relativity. Is there a method for obtaining the metric tensor exterior to a specified mass distribution numerically? In the simplest case of a spherical mass this should ...
Martin C.'s user avatar
  • 1,741
19 votes
3 answers
3k views

How does one measure space-like geodesics? Or: What is the physical interpretation of space-like geodesics?

In general relativity, time-like geodesics are the trajectories of free-falling test particles, parametrized by proper time. Thus, they are easy to interpret in physical terms and are easy to measure (...
Marc's user avatar
  • 475
18 votes
2 answers
18k views

Lowering/raising metric indexes

So, I was chatting with a friend and we noticed something that might be very, very, very stupid, but I found it at least intriguing. Consider Minkowski spacetime. The trace of a matrix $A$ can be ...
QuantumBrick's user avatar
  • 4,113
18 votes
5 answers
21k views

Why is the space-time interval squared?

The space-time interval equation is this: $$\Delta s^2=\Delta x^2+\Delta y^2+\Delta z^2-(c\Delta t)^2$$ Where, $\Delta x, \Delta y, \Delta z$ and $\Delta t$ represent the distances along various ...
Christopher King's user avatar
18 votes
5 answers
2k views

In general relativity, are two pseudo-Riemannian manifolds physically equivalent if they are isometric, or just diffeomorphic?

In Carroll's Appendix B, he says You will often hear it proclaimed that GR is a "diffeomorphism invariant" theory. What this means is that, if the universe is represented by a manifold $M$ with ...
tparker's user avatar
  • 49.4k
18 votes
2 answers
899 views

Metric of an Evaporating Black Hole

The famous Hawking calculation is done with an assumption that the background is static, i.e. the evaporation doesn't change the mass parameter in the metric. Thus, we simply describe the geometry ...
user avatar
17 votes
9 answers
3k views

"Gauge Freedom" in GR

When we derive the equations for propagating waves in GR, we have to make a gauge choice to get something unique. I understand that in electromagnetism, the gauge is not in general something ...
Eric David Kramer's user avatar
17 votes
3 answers
7k views

Deriving Birkhoff's Theorem

I am trying to derive Birkhoff's theorem in GR as an exercise: a spherically symmetric gravitational field is static in the vacuum area. I managed to prove that $g_{00}$ is independent of $t$ in the ...
toot's user avatar
  • 2,926
17 votes
3 answers
4k views

Advantages of using different metric signatures in relativity and QFT

I am studying General Relativity and some basic QFTs. It bothers me a lot that different books use different metric signatures, i.e. $(-+++)$ and $(+---).$ Can anyone tell me the advantages of using ...
Allen Chiu's user avatar
17 votes
3 answers
3k views

Proving invariance of $ds^2$ from the invariance of the speed of light

I've started today the book of Landau and Lifshitz Vol.2: The Classical Theory of Fields $\S 2$. They start from the invariance of the speed of light, express it as the fact that $$c^2(\Delta t)^2-(\...
user35543's user avatar
  • 171

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