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57 votes
4 answers
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Hilbert space of harmonic oscillator: Countable vs uncountable?

Hm, this just occurred to me while answering another question: If I write the Hamiltonian for a harmonic oscillator as $$H = \frac{p^2}{2m} + \frac{1}{2} m \omega^2 x^2$$ then wouldn't one set of ...
Lagerbaer's user avatar
  • 14.8k
29 votes
3 answers
3k views

Do states with infinite average energy make sense?

Do states with infinite average energy make sense? For the sake of concreteness consider a harmonic oscillator with the Hamiltonian $H=a^\dagger a$ and eigenstates $H|n\rangle=n|n\rangle$, $\langle n|...
Weather Report's user avatar
26 votes
2 answers
9k views

Proof that the one-dimensional simple harmonic oscillator is non-degenerate?

The standard treatment of the one-dimensional quantum simple harmonic oscillator (SHO) using the raising and lowering operators arrives at the countable basis of eigenstates $\{\vert n \rangle\}_{n = ...
Evan Sosenko's user avatar
12 votes
3 answers
10k views

Why Don't the Ladder Operators Commute?

I have two problems with ladder operators. The first is that I feel they should somehow result in measurable things. The asymmetry of applying the plus operator versus the minus operator is very ...
user avatar
10 votes
2 answers
12k views

Eigenstates of a shifted harmonic oscillator

Let's say I have a quantum harmonic oscillator $H = \omega a^\dagger a$, where $a^\dagger$ is the raising operator and $a$ is the lowering operator and $H |n\rangle = \omega n |n\rangle$. Now assume ...
physicsGuy's user avatar
  • 1,022
10 votes
1 answer
3k views

Creating a QM state of definite position in Fock space

I'm wondering if somebody could help me to finish a simple calculation. Let me first provide motivation for the question below: I would like to write a QM amplitude in the 'QFT-style', as $$\langle \...
mavzolej's user avatar
  • 2,852
9 votes
4 answers
871 views

Ladder operator identity for $\langle n | (a+a^\dagger)^k | m \rangle$

I would like to know if there is a convenient identity (and what it is) for $$\langle n | (a+a^\dagger)^k | m \rangle$$ where $| n \rangle, \, | m \rangle$ are energy eigenstates of a simple ...
Diffycue's user avatar
  • 1,020
9 votes
2 answers
944 views

Do the ladder operators $a$ and $a^\dagger$ form a complete algebra basis?

It is easy to construct any operator (in continuous variables) using the set of operators $$\{|\ell\rangle\langle m |\},$$ where $l$ and $m$ are integers and the operators are represented in the Fock ...
Aharon Brodutch's user avatar
9 votes
1 answer
805 views

Proof that $\exp(-\beta H)$ is a trace-class operator for the harmonic oscillator

Let $H=\frac{p^2}{2}+\frac{x^2}{2}\, : D(H) \to L^2(\mathbb{R})$ be the Hamiltonian of the harmonic oscillator with $m=\hbar=\omega=1$. Prove that $\exp(-\beta H)$ is a trace-class operator if $\beta&...
th_phys's user avatar
  • 507
7 votes
3 answers
4k views

Why is the action of lowering operator on the ground state of a harmonic oscillator to give a 0 wave function?

In quantum mechanics of the harmonic oscillator, when we use the operator method to find out the solutions, we find that the action of $\hat{a}$ is to lower the energy of a state by $\hbar\omega$ and ...
Tachyon209's user avatar
7 votes
1 answer
164 views

How to get the factor of $n^{-27/4}$ in number of open string states from the calculation in GSW's book?

In section 2.3.5 of Green, Schwarz, Witten's book on string theory (volume-1) pp. 116-118, the objective is to calculate an Asymptotic Formula for Level Densities $d_n$ for open bosonic string theory. ...
Sanjana's user avatar
  • 414
6 votes
2 answers
14k views

How To Use Ladder Operators?

I'm studying for a test in quantum mechanics and I'm having a hard time understanding how to use ladder operators. There are no examples in my text book, only definitions that I can't understand how ...
Djamillah's user avatar
  • 463
6 votes
1 answer
609 views

Orbital angular momentum as sum of harmonic oscillators

On section 7.3 of Ballentine's "Quantum Mechanics: A Modern Development" there is a really nice argument on why the eigenvalues of the total angular momentum operator must be integer, cf. e....
dnvlz's user avatar
  • 93
6 votes
2 answers
612 views

Non-integer powers for the quantum harmonic oscillator ladder operators and spectrum uniqueness

Introduction (The idea to this question came from my answer to Uniqueness of quantum ladder for the harmonic oscillator) The Hamiltonian $H$ for quantum harmonic oscillator can be written in terms ...
Joca Ramiro's user avatar
5 votes
1 answer
2k views

The issue on existence of inverse operations of $a$ and $a^{\dagger}$

I have asked a question at math.stackexchange that have a physical meaning. My assumption: Suppose $a$ and $a^\dagger$ is Hermitian adjoint operators and $[a,a^\dagger]=1$. I want to prove that ...
Oiale's user avatar
  • 1,014
5 votes
2 answers
2k views

Why do the ladder operators in harmonic oscillators work?

The Hamiltonian can be diagonalized by transforming $x$ and $p$ to $a$ and $a^\dagger$. I understand how one proceeds from there to find the spectrum of $a^\dagger a$, the ground state $|0\rangle$ and ...
Martin Ueding's user avatar
5 votes
2 answers
970 views

Coherent states of Quantum harmonic oscillator

Coherent states of Quantum harmonic oscillator . The Hamiltonian of Quantum harmonic oscillator is $H=(a^+ a+\frac{1}{2})\hbar \omega$,$a=\sqrt{\frac{m \omega}{2 \hbar}}(\hat{x}+\frac{i \hat{p}}{m \...
Young1997's user avatar
5 votes
2 answers
1k views

Quantization of an Hamiltonian

My question is the following : I am studying a 1D harmonic oscillator chain. My classical hamiltonian contains terms such as $U_n$ where $U_n=x_n-x_n^0$, it represents the position away from ...
StarBucK's user avatar
  • 1,350
5 votes
0 answers
3k views

Position and momentum eigenstates in terms of creation and annihilation operator? [closed]

Consider a simple harmonic oscillator; the position operator is $\hat{x}=(a^\dagger+a)/\sqrt{2}$ and the momentum operator is $\hat{p}=-i(a-a^\dagger)/\sqrt{2}$. One may verify that the eigenstates ...
Nahc's user avatar
  • 2,071
4 votes
1 answer
771 views

Intuition behind creation and annihilation operators? [duplicate]

Here I am talking about Harmonic Oscillators with Hamiltonian $$ H=\frac{1}{2m}(p^2+(m\omega x)^2), $$ with eigenstates $|1\rangle,|2\rangle,\ldots$ Many textbooks define the annihilation operator to ...
Ma Joad's user avatar
  • 1,315
4 votes
3 answers
222 views

How to express $|m\rangle\langle n|$ in terms of ladder operators?

Let us consider the Hamiltonian of a single harmonic oscillator, which is expressed in terms of creation/annihilation operators as $H=\hbar \omega (a^{\dagger}a+1/2)$. The eigenstates of this ...
Tan Tixuan's user avatar
4 votes
3 answers
832 views

Is the zero point energy of this system zero?

Consider the following Hamiltonian: $$\hat H=\frac{\hbar\omega}{2}(\hat x^2+\hat p^2)-\frac{\hbar\omega}{2}\hat 1 =\frac{\hbar\omega}{2}(\hat x^2+\hat p^2-\hat 1 )$$ After defining annihilation and ...
Lost's user avatar
  • 1,431
4 votes
1 answer
268 views

On the two different solution approaches of the quantum harmonic oscillator

The Hamiltonian for the harmonic oscillator (with $\hbar = m = 1$) is given by: $$\hat{H} = -\frac{1}{2}\frac{d^{2}}{dx^{2}} + \frac{1}{2}\omega^{2}x^{2}$$ This is assumed to be an operator on $\...
MathMath's user avatar
  • 1,123
4 votes
3 answers
3k views

What is the Hamiltonian in the "energy basis" for a simple harmonic oscillator?

My textbook says that for a simple harmonic oscillator the Hamiltonian can be expressed in the "energy basis" in this way: $$\hat H=\hbar\omega\bigg(\hat a^{\dagger}\hat a + {1\over 2}\bigg).$$ I ...
matryoshka's user avatar
4 votes
1 answer
343 views

Individual particle states in Fock space

I am currently learning QFT, and after watching the wonderful lectures by Leonard Susskind (https://theoreticalminimum.com/courses/advanced-quantum-mechanics/2013/fall), I am still struggling to see ...
Dmitry Pugachev's user avatar
4 votes
2 answers
2k views

Meaning of Harmonic oscilator correlation function In Quantum Mechanics

What is the physical interpretation of the quantity $$\xi(t)=\langle 0|x(t)x(0)|0\rangle=\frac{\hbar}{2m\omega}e^{-i\omega t}$$ where $|0\rangle$ is the ground state of the harmonic oscillator? I know ...
SRS's user avatar
  • 26.4k
3 votes
4 answers
810 views

Hamiltonian of quantum harmonic oscillator with $\psi(x)=\delta(x)$: comparison to classical mechanics

I was just reading the question Why can't $\psi(x)=\delta(x)$ in the case of a harmonic oscillator? The accepted answer says that $\psi(x)=\delta(x)$ is a mathematically valid state, though it's not ...
user avatar
3 votes
2 answers
274 views

Meaning of "the symmetry group of an $N$-dimensional quantum isotropic oscillator is $U(N)$"

Symmetry of this system has been discussed here but I'm still confused. Consider a $N$-dimensional isotropic harmonic oscillator, with hamiltonian $$H = \hbar \omega \left(a^\dagger_i a_i + \frac{N}{2}...
confused_nevin's user avatar
3 votes
1 answer
420 views

Do Hermite polynomials imply a weight for quantum harmonic oscillator wavefunctions?

I know that solutions of quantum harmonic oscillator can be expressed in the form of Hermite polynomials. But I recently came to know that Hermite polynomials are actually orthogonal polynomials ...
baba26's user avatar
  • 431
3 votes
1 answer
266 views

Why is the degeneracy of the 3D isotropic quantum harmonic oscillator finite?

This is a more conceptual question. When we take the isotropic harmonic oscillator: $$V = \frac{1}{2}m\omega^2(x^2+y^2+z^2)$$ the eigenvalue equation solves to: $$\phi_E=\phi_l(x)\phi_m(y)\phi_n(z)$$ ...
The Feadow's user avatar
3 votes
3 answers
233 views

Procedure to cut an Harmonic oscillator to two first level to obtain a qubit

Let us consider a (quantum) Harmonic oscillator: $$H=\frac{p^2}{2m}+\frac{1}{2} m \omega^2 x^2$$ Using the annihilation/creation operators defined as: $$a=\sqrt{\frac{\hbar}{2 m \omega}}(x+\frac{i}{m \...
StarBucK's user avatar
  • 1,350
3 votes
3 answers
551 views

When Is It Appropriate To Use The Ladder Operator Method in Quantum Mechanics?

I'm trying to understand when it is intuitively obvious that the ladder method would be best used to tackle a problem in quantum mechanics.
Qubit's user avatar
  • 401
3 votes
1 answer
559 views

Confusion about modes and quantum field theory

I'm learning quantum field theory from P&S and Srednicki. I'm having a lot of difficulties understanding the concept of a momentum state. In particular, I'm confused about how to interpret the ...
user avatar
3 votes
1 answer
331 views

Why can't $\psi(x) = \delta(x)$ in the case of Harmonic oscillator?

In the analysis of Harmonic Oscillator, it is claimed that $\langle\hat H\rangle$ cannot be zero, why is it so? I mean $\hat H = \frac{ \hat p^2 }{2m } + \frac12 k \hat x^2$, and $$\left<x^2\...
Our's user avatar
  • 2,263
3 votes
1 answer
699 views

Relation between the bosonic harmonic oscillator and the 'ordinary' harmonic oscillator

What exactly is the connection between the Harmonic oscillator that we study in Quantum Mechanics I, and the bosonic (and fermionic) harmonic oscillator ? In some sources, it is claimed that my '...
RayPalmer's user avatar
  • 483
3 votes
1 answer
769 views

Why does the virial theorem of quantum mechanics hold for the quantum oscillator but not the infinite square well?

Why does the virial theorem of quantum mechanics hold for the quantum oscillator but not the infinite square well? The proof uses Ehrenfest's theorem, so I was wondering if it had something to do with ...
Buddhaha's user avatar
3 votes
2 answers
3k views

The harmonic oscillator - ladder operators

Reading from Griffiths. I have got two questions. First, the halmiltonian operator that used to find the energy eigenvalue in only harmonic oscillator is: $$H={\hbar}w(a_-a_+-\frac{1}{2})$$ and $$H={\...
Outrageous's user avatar
3 votes
1 answer
89 views

Proof that the QHO annihilation operator has nullity of 1

In a traditional analysis of a quantum harmonic oscillator (QHO), operators $a$ and $a^\dagger$ are introduced and it is shown that $$ H a |{n}\rangle = (E_n - \hbar \omega_0)a|{n}\rangle, $$ $$ H a^\...
jamman2000's user avatar
3 votes
2 answers
774 views

Quantum Mechanics Basics: product space

Consider a coupled harmonic oscillator with their position given by $x_1$ and $x_2$. Say the normal coordinates $x_{\pm}={1\over\sqrt{2}} (x_1\pm x_2)$, in which the harmonic oscillators decouple, ...
Nilanjan's user avatar
  • 163
3 votes
2 answers
397 views

Relation between destruction/creation operators of harmonic oscillator in QM and Second Quantization

It is well known that in elementary QM the so-called destruction/creation operators $$ a_i = \frac{Q_j + i P_j }{\sqrt{2}}, \quad a_i^* = \frac{Q_j - i P_j }{\sqrt{2}},$$ are introduced when ...
ErroDSF's user avatar
  • 33
3 votes
2 answers
681 views

Harmonic Oscillator - Energy quantisation

The one-dimensional quantum HO can be solved in Schrodinger representation by getting Hermite Differential Equation $$ \frac{d^2y}{dx^2} - 2x \frac{dy}{dx} + \lambda y = 0 $$ with solutions $$ y(x) = ...
user35952's user avatar
  • 2,975
3 votes
2 answers
207 views

Question about lowest rung on Harmonic Oscillator

I'm reading Griffiths's Introduction to Quantum Mechanics 3rd ed textbook [1]. On p.43, the author explains: What if I apply the lowering operator repeatedly? Eventually I’m going to reach a state ...
Arete's user avatar
  • 441
3 votes
1 answer
557 views

State time evolution of a quantum harmonic oscillator with a Dirac-Delta function as an initial state [closed]

I have a question just like this Phys.SE problem here with a difference that our system is a harmonic oscillator (rather than a free particle). A particle with mass $m$ is connected to a string with ...
Abolfazl's user avatar
  • 431
3 votes
0 answers
197 views

Creating an arbitrary state of the quantum simple harmonic oscillator

Suppose $\mathcal{B}=\{|0\rangle, |1\rangle, |2\rangle, ... \}$ is the energy eigen-basis of a quantum simple harmonic oscillator. I want to create the state \begin{equation} |\Psi\rangle = c_{0}|0\...
Mustapha Mond's user avatar
2 votes
3 answers
3k views

How does one calculate the position eigenvalues of the matrix corresponding to the position operator?

The matrix representation corresponding to the position operator is: $$x = \sqrt{\frac{\hbar}{2 m \omega}} \left[ \begin{array}{ccccc} 0 & \sqrt{1} & 0 & 0 & \cdots \\ \sqrt{1} & ...
Deschele Schilder's user avatar
2 votes
3 answers
557 views

What is the physical meaning of $a_{\vec{p}} \! \mid \! 0 \rangle$

$a^\dagger_{\vec{p}} \! \mid \! 0 \rangle = \mid \! p \rangle$ is interpreted as a creation of a particle with momentum $p$ from the vacuum. $a_{\vec{p}} \! \mid \! p \rangle = \mid \! 0 \rangle$ is ...
Dargscisyhp's user avatar
  • 5,319
2 votes
3 answers
583 views

Simple harmonic oscillator by operators

I'm reading simple harmonic oscillator problem in "Modern Quantum Mechanics" by J.J. Sakurai. The approach is by defining the annihilation ($a^{t}$) and creation ($a$) operators, then a number ...
Alberto Navarro's user avatar
2 votes
1 answer
228 views

Coherent state calculation of $\left<\lambda|x^2|\lambda\right>$, getting two different answers?

Getting a strange result here. I am studying the Quantum Harmonic oscillator and dealing with coherent states. I know that I can expand the position operator as $x = \sqrt{ \frac{\hbar}{2 m \omega} } ...
QuantumEyedea's user avatar
2 votes
3 answers
18k views

Degeneracy of 2 Dimensional Harmonic Oscillator

If we consider a particle in a 2 dimensional harmonic oscillator potential with Hamiltonian $$H = \frac{\mathbf{p}^2}{2m} + \frac{m w^2 \textbf{r}^2}{2}$$ it can be shown that the energy levels are ...
user avatar
2 votes
1 answer
929 views

Expectation value in the ground state of simple harmonic oscillator

Motivated by a problem in chapter 2 of Sakurai's book Modern Quantum Mechanics, I'm interested in confirming something about the simple harmonic oscillator in quantum mechanics, I have found that the ...
user avatar