All Questions
9 questions
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Vibrational degree of freedom for monoatomic gases
I read that, when the temperature of a gas becomes high enough, a third type of degree of freedom becomes accessible, viz. the vibrational degree of freedom.
Also (at high temperatures) there is a ...
0
votes
1
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758
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Number of degrees of freedom for a gaseous mixture
I came across the formula to find the number of degrees of freedom in a gaseous mixture which is as follows:
$$f_\mathrm{mix}
=\frac{\sum n_if_i}{\sum n_i}$$
Now it has been mentioned in this lecture ...
0
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1
answer
300
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Does the ideal gas law apply to gases which consist of more than one atom?
In the derivation of the ideal gas law, one sets for the average kinetical energy $f = 3$ degrees of freedom. This refers to the transition in x,y,z axes. This is true for gases, which consist of only ...
- 361
1
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1
answer
201
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Number of degrees of fredom in diatomic molecule model
In the book of Salinas the author says in chapter The Ideal Quantum Gas he says and I quote
The classical models of a gas of diatomic molecules (a rigid rotator in three dimensions, or a rotator ...
user78217
2
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1
answer
87
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Kinetic theory of physics [closed]
$$E = (3/2) kT$$
For average kinetic energy of a molecule gas.The constant $k$ does not depend on the type of molecule. Can this result be true for both hydrogen and chlorine?
- 21
6
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2
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13k
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Why energy at room temperature $= kT$ and not $(3/2)kT$ [duplicate]
I always see that a room temperature of $T=300\,\text{K}$ corresponds to an energy of $k_BT \approx \frac{1}{40}\,\text{eV}$. But shouldn't it be $\frac{3}{2}k_BT$ since the molecules in the air have ...
- 163
2
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1
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3k
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Why is molar specific heat at constant volume of a monatomic ideal gas a constant?
I thought specific heat varies depending on the substance. Why is it always $(3/2) R$?
- 143
4
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3
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6k
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$E=kT$ or $\frac32kT$?
Basically, which is the correct formula for thermal energy, and is this the same as kinetic energy? My notes are pretty conflicting on this topic, and I'm getting pretty confused.
- 51
16
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7
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142k
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How to deduce $E=(3/2)kT$?
It says in my course notes for undergraduate environmental physics that a particle has so-called "kinetic energy"
$$E=\frac{3}{2}kT=\frac{1}{2}mv^{2}$$
Where does this formula come from? What is $k$?...
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