Questions tagged [commutator]

A mathematical construct quantifying the difference in effect of applying two operators in two alternate successions. It is the defining product of a Lie algebra, the efficient underlying description of Lie groups, of use in several areas of physics, most notably quantum field theory.

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Canonical transformations in Quantum Mechanics

Heisenberg's famous commutator of a pair of conjugated canonical variables is formulated for position and conjugated momentum $$[q,p] = i\hbar.$$ Intuitively I would guess that it would also work ...
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How does Dirac prove that the canonical coordinates $q_r$ form a complete commuting set of observables?

I'm reading "The principles of quantum mechanics" by Paul Dirac, and I've reached the point where he introduces the momentum operator. After showing that the $p_r$'s commute with each other ...
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If an operator $A$ commutes with the Hamiltonian $H$ do they have common eigenstates?

In this book Intermediate quantum mechanics by Hans A. Bethe and Roman Jackiw they write at page 103: In the case of spin, the Hamiltonian commutes with the spin operator of each electron $\...
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Question about commutator involving fermions and Pauli matrices [closed]

Suppose $\lambda_A$ and $\bar{\lambda}_A$ are fermions (A goes from 1 to N) and $\{ \lambda_{A \alpha}, \bar{\lambda}_B^{\beta}\} = \delta_{AB}\delta_{\alpha}^{\beta}$. Let $\sigma^i$ denote the Pauli ...
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Exponential operator approximation: Suzuki-Trotter Expansion

One cannot solve the transition amplitude $\langle{x}\vert e^{-iHt}\vert{y}\rangle{}$ with $H=H_0+V$ by just applying the operators one after another on the bra/ket, because the free hamiltonian $H_0$ ...
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Are partition functions invariant under Bogoliubov transformations?

Consider a Hamiltonian $H(a_i, a^{\dagger}_i)$ as a function of some ladder operators $a_i, a^{\dagger}_i$. Now, consider a partition function $H(a'_i, a'^{\dagger}_i)$ where $a', a'^{\dagger}$ are ...
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Uncertainty on the sum of two non-commuting operators

Suppose that I have an observable $$ \hat{E} = \sin(\alpha) \hat{Q} + \cos({\alpha}) \hat{P} $$ with $\hat{Q}, \hat{P}$ being non-commuting operators satisfying $$ [\hat{Q}, \hat{P}] = i \hbar $$ It ...
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From Klein-Gordon equation to Dirac equation: a wrong "derivation" [closed]

So let us start with the Klein-Gordon equation $$\tag{KG} (-p^\mu p_\mu + m^2)\phi = 0 $$ The idea is to "factorize" the operator $-p^\mu p_\mu + m^2$. \begin{equation}\tag{1} -p^\mu p_\mu + ...
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Non-vanishing amplitude outside light cone doesn't violate causality? [duplicate]

I am following Peskin & Schroeder's QFT book. And on equation 2.51, we get an expression for the free Klein-Gordon propagator for timelike intervals $x^0-y^0=t$, $x-y=0$: $$D(x-y) \sim e^{-imt}\...
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Commutation relation between pairs of conjugated variables

Suppose I have four operators $\hat{q}_1$, $\hat{p}_1$, $\hat{q}_2$ and $\hat{p}_2$ such that $[\hat{q}_1, \hat{p}_1] = [\hat{q}_2, \hat{p}_2] = i$ $[\hat{q}_1, \hat{q}_2] = [\hat{p}_1, \hat{p}_2] = [...
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Deriving $\hat{p}_ x =-iℏ∂/∂x$ [duplicate]

(Taken from "The meaning of Quantum Theory, from Jim Baggott). Starting from [x,^Px]= iℏ, if we chose the position operator to be simply 'multiplication by x', this forces the linear momentum ...
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Commutation relation of position and Hamiltonian operator [duplicate]

In the book Quantum Mechanics volume 2 by Cohen-Tannoudji, in Electric dipole approximation, it was written that $\left[\boldsymbol{Z}, H_0\right]=i \hbar \frac{\partial H_0}{\partial P_{\boldsymbol{z}...
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Commutable operators and eigenfunctions

My lecture notes says Since $[\hat{L^2} ,\hat{L_{z}}] = 0$ Then $Y(\theta,\phi)$ solves the below equations simultaneously: $$\hat{L^2}Y(\theta,\phi) = A Y(\theta,\phi)$$ $$\hat{L_{z}}Y(\theta,\phi) = ...
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Momentum operator and Space operator

This may be a silly question, but given that the momentum operator (say in the $x$-direction) can be written as $$p_x = -i \hbar \frac{\partial}{\partial x},$$ would it be correct to say that $$p_x^2 ...
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Canonical Commutator Relation from Translation operator

In the book of Sakurai & Napolitano, the Canonical Commutation relation is derived using the unitary translation operator: I agree with the derivation of the book until i reach this step, and ...
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Quantization of radiation with canonical conjugate variables

I am reading the Introduction to quantum optics book and I am a bit stuck at the quantization of electromagnetic field (around page 317). The problem in this case is that we can't just express the ...
Nicolas Schmid's user avatar
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Why is $[ \hat{A},\hat{B} ] \rightarrow i \hbar \text{{A, B}}$?

If we have two classical quantities $A$, $B$, and their corresponding quantum operators $\hat{A}$, $\hat{B}$, then their commutators and Poisson brackets are linked by $$ [ \hat{A},\hat{B} ] \...
Nicolas Schmid's user avatar
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Why do we only consider commutators and anticommutators in QFT?

While studying canonical quantization in QFT, I observed that we quantize fields either by a commutation or an anticommutation relation \begin{equation} [\phi(x), \phi(y)]_\pm := \phi(x) \phi(y) \pm \...
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Dressing an operator by Wilson line in Quantum Electrodynamic

I am reading a paper arXiv:1507.07921 which introduce gravitational dressing. The paper compare it to dressing in QED. Consider the scalar QED lagrangian $$\mathcal{L}=-\frac{1}{4}(F^{\mu\nu})^2-|D_\...
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How to correctly use the Mean-Field Approximation to simplify a Commutation Relation in Excitonic Physics?

I am following the work in 'Theoretical Methods for Excitonic Physics in 2D Materials'1. They are aiming to derive the BSE equation for exciton physics. I am however stuck on the use of the Mean-field ...
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Proving Non-degenerateness for Compatible observables [closed]

Hi everybody I was trying to verify the following fact but I've been having some trouble. I need to prove that if $A,B$ are two compatible observables and their eigenvalues are non-degenerate, then ...
Claudio Menchinelli's user avatar
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What's the inverse of an adjoint endomorphism?

$\def\ada{\text{ad}_A}$Suppose $A,B$ are operators in Quantum Mechanics, the adjoint endomorphism $\text{ad}_A$ can be expressed by $$ \text{ad}_A B=[A,B]=AB-BA $$ and $$\text{ad}_A^0B=B, \quad \ada^n ...
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Commutation relations for angular momentum operators [closed]

I was reading Sakurai's Quantum Mechanics and I'm having some trouble with the following computation: I need to verify that: $$[ S_i, S_j] = i \hbar \epsilon_{ijk}S_k , i \in \{1,2,3\}$$ For $i = 1,y ...
Claudio Menchinelli's user avatar
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Set of Compatible Observables and Simultaneous Eigenkets Basis

I have managed to prove that a finite set of compatible observables [i.e. pairwise commuting (possibly unbounded) selfadjoint operators] on an Hilbert space $\{H\}$ admits an orthonormal basis of ...
Matteo Menghini's user avatar
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Maximality and Completeness for Set of Compatible Observables

Let $\mathcal{A} = \{A_j\}_{j=1}^{N}$ be a finite family of compatible observables (they commute pairwise) on an Hilbert space $H$. Consider the following definitions: $\mathcal{A}$ is Maximal if and ...
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If something commutes with $x$, it commutes with any $f(x)$

I often read that if some operator commutes with (say) the position operator $x$, it commutes with any function $f(x)$ of it. For analytical functions, this is obvious, but I was wondering if there ...
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Do operators commute if they depend on the same operator? [duplicate]

Consider two arbitrary operators $\hat{A}(\hat{R})$ and $\hat{B}(\hat{R})$ that are both functions of the position operator $\hat{R}$ (and do not depend on any other operators). Does it follow that $$[...
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Can I upper-bound uncertainties of $B$ in an eigenstate of $A$ using an appropriate norm of $[A,B]$?

There are times when I would really like a "reverse" uncertainty principle to hold, allowing me to upper-bound certain uncertainties in terms of properties of commutators. I'll try to ...
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Commutator of gamma matrices with scalar product of 4-vectors

I know about the commutator relationship given in this question: $$\left[\gamma^{\mu},\gamma^{\nu}\right]=2\gamma^{\mu}\gamma^{\nu}-2\eta^{\mu\nu}$$ then, my question is if there exist a similar ...
Lluis Gerardo's user avatar
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What went wrong in the following calculation of $\langle p'|[x,p]|p'\rangle$? [duplicate]

We know that $$[x,p]=i\hbar. $$ Consider now the diagonal element in the momentum representation, $$\langle p'|[x,p]|p'\rangle=i\hbar\langle p'|p'\rangle=i\hbar\delta(0).$$ But the LHS = $$\langle p'|...
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How can difference of two operators produce a constant?

In the canonical commutation relations, $$[\hat{x}, \hat{p}] = \hat{x}\hat{p} - \hat{p}\hat{x} = i \hbar $$ Both $\hat{x}$ and $\hat{p}$ are operators and so are $\hat{x}\hat{p}$ and $\hat{p}\hat{x}$. ...
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A simple question on creation and annihilation operators

We know that the KG solution for a Spin-0 particle has the following Hamiltonian $$\hat{H}=∫ d^{3}p\frac{ω_{p}}{2}(\hat{a}_{p}\hat{a}^{\dagger}_{p}+\hat{a}^{\dagger}_{p}\hat{a}_{p})\hspace{2cm}[\hat{a}...
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Strange definition of the fermion number operator in Polchinski

In Polchinski's exposition of the RNS formalism for the superstring (String Theory: Volume II, chapter 10), in page 8, he mentions the worldsheet fermion number operator, which he calls $F$. He then ...
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Commutator of annichilation and creation operators [closed]

Let $\phi$ be a real scalar field and $\psi$ a complex scalar field. Therefore, we can expand $\phi$ in terms of $a_{\boldsymbol{p}}, a^\dagger_{\boldsymbol{p}}$ and $\psi$ in terms of $b_{\boldsymbol{...
Alex's user avatar
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Operators depending on the same independent variable but commuting between them [closed]

As far as I understood in quantum mechanics two operators can commute even though they are not functionally independent, which means that they can depend on the same independent variable. On the other ...
faber's user avatar
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Rotor wave fomulation of quantum mechanics and the associated canonical commutation relations of position and momentum operators

I've been trying to determine whether it would be possible to formulate non-relativistic quantum mechanics entirely in the algebra of physical space (APS) by using rotor waves instead of complex-...
brainandforce's user avatar
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Commuting operators and their physical interpretation in QM

I'm studying Quantum Mechanics for the first time at the moment and I have a few questions in mind. So recently, I saw a proof on that if two operators share the same eigenstates is equivalent to the ...
Tanamas's user avatar
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Do position and spin commute?

I recently learned that position vectors and spin vectors lie in different spaces, and the complete wave is the tensor product of both. I wanted to know that whether we can talk about commutation of ...
veke's user avatar
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Product of normally ordered exponentials as a normal ordering of product of exponentials

I want to simplify a product of normally ordered exponentials that are in the following form $$:e^{x(\hat{a}^\dagger+\alpha_x^*)(\hat{a}+\alpha_x)}:\times :e^{y(\hat{a}^\dagger+\alpha_y^*)(\hat{a}+\...
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Matrix element of two operators, where one does not commute with the operators of the basis kets

If I am considering 2 operators A and B and an initial basis $|F,m_F\rangle$ , where F is the total angular momentum operator of the two systems. While assuming that operator A does commute with $\vec ...
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Variable Dependence of Quantum Operators and Commutator Relationships [duplicate]

EDIT: After doing some digging, I am convinced that the approach taken in this paper was simply an incorrect approach to deriving a quantum version of Hamilton's equations (also related to Ehrenfest's ...
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Showing that time ordering does not matter for the measurement of commuting observables

Suppose I have two observables $R$ and $S$ who are represented by operator $R$ and $S$ which commute (I will hereafter ignore the distinction between observables and the operators representing them), ...
EE18's user avatar
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Time-ordered exponential operator generated by two commuting Hamiltonians

Define a time-dependent Hamiltonian $$H(t) = H_1(t) + H_2(t),\tag{1}$$ where $$[H_1(t), H_2(t)] = 0 ~ \forall t \in [0,T].\tag{2}$$ Is it true that the unitary operator generated by $H(t)$ is a ...
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Why can't commuting operators allow for full state determination?

For the purposes of this question, suppose that the operator $R$ representing the observable $\mathsf{R}$ has nondegenerate eigenspaces. In discussing state determination (for some given situation, ...
EE18's user avatar
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Why does $[L_z,L_{\pm}]\neq 0$ imply $[J^2,L_z]\neq 0$?

In a lecture about the angular momentum operator, it is stated that the operator $L_z$ commutes with itself, with $L^2$, with all of spin angular momentum operators, but not with $L_{\pm}$, so; $$[J^2,...
Rasmus Andersen's user avatar
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Angular momentum commutator in QFT/the roles of coordinates

this is my first question on this site, so please correct me if I break any convention. It arose as part of homework, but I suppose that there is some deeper irritation behind it. We are supposed to ...
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For hydrogen atom wave function, why eigenstate of Hamiltonian isn't only spherical harmonics if $H$ commutes with square of angular momentum? [closed]

I was reading quantum mechanics and I read about CSCO. So, commuting operators should share common eigen states, does that mean same eigen states? because in hydrogen atom wave function, Hamiltonian ...
Shuvajit Dutta's user avatar
3 votes
2 answers
143 views

What is the value of the commutator $[L_x, S_y]$? [closed]

I would like to know how to calculate the commutator $[L_x, S_y]$ in quantum mechanics, if $L_x$ is the x-component of the angular momentum operator and $S_y$ the y-component of the spin operator. I ...
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Integrals and Laplace Operator with a Commutator

If I have a Hamiltonian which looks like: $H=\int_{}^{} \psi(x)^\dagger \nabla^2_{x} \psi(x)d^3x $ and a total number operator like: $N=\int_{}^{} \psi(x)^\dagger \psi(x)d^3x $ and I want to ...
Chrononaut's user avatar
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Canonical Commutation relations in gravity

The canonical commutation relations in gravity are sometimes written $$ [\gamma_{ij}(x),\pi^{kl}(y)]=\frac{i\hbar}{2}(\delta_i^k\delta_j^l+\delta_i^l\delta_j^k)\delta^3(x-y),\tag{0} $$ where $\gamma_{...
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