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0 votes
1 answer
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What is the physical meaning of commuting in quantum mechanics? [duplicate]

In quantum mechanics, if two observables commute, then perfect knowledge can be gained about both observables simultaneously. But what does the commutator actually, physically represent? Like ...
Shantanu's user avatar
  • 369
111 votes
15 answers
16k views

Why quantum mechanics?

Imagine you're teaching a first course on quantum mechanics in which your students are well-versed in classical mechanics, but have never seen any quantum before. How would you motivate the subject ...
Jonathan Gleason's user avatar
134 votes
8 answers
39k views

What is $\Delta t$ in the time-energy uncertainty principle?

In non-relativistic QM, the $\Delta E$ in the time-energy uncertainty principle is the limiting standard deviation of the set of energy measurements of $n$ identically prepared systems as $n$ goes to ...
Hobo's user avatar
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60 votes
7 answers
95k views

What is the Physical Meaning of Commutation of Two Operators?

I understand the mathematics of commutation relations and anti-commutation relations, but what does it physically mean for an observable (self-adjoint operator) to commute with another observable (...
adustduke's user avatar
  • 823
27 votes
3 answers
4k views

The geometrical interpretation of the Poisson bracket

"Hamiltonian mechanics is geometry in phase spase." The Poisson bracket arises naturally in Hamiltonian mechanics, and since this theory has an elegant geometric interpretation, I'm interested in ...
Samà's user avatar
  • 477
25 votes
2 answers
3k views

Does the poisson bracket $\{f,g\}$ have any meaning if neither of $f$ or $g$ is the system's Hamiltonian?

Say one has a mechanical system with hamiltonian $H$, and two other arbitrary observables $f,g$. $H$ is super useful since $\{H, \cdot\} = \frac{d}{dt}$. But does $\{f,g\}$ give any useful information ...
Brian Burns's user avatar
26 votes
2 answers
14k views

What is the physical meaning of anti-commutator in quantum mechanics?

I gained a lot of physical intuition about commutators by reading this topic. What is the physical meaning of commutators in quantum mechanics? I have similar questions about the anti-commutators. ...
khalid's user avatar
  • 281
10 votes
3 answers
4k views

Reason for Uncertainty principle

$$\Delta x \Delta p_x \geq \frac{\hbar}{2} $$ I understand what does Heisenberg's uncertainty principle states i.e. it's definition and it has been proven experimentally. But, can anyone please ...
23rduser's user avatar
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15 votes
1 answer
6k views

What is the physical interpretation of the Poisson bracket [duplicate]

Apologies if this is a really basic question, but what is the physical interpretation of the Poisson bracket in classical mechanics? In particular, how should one interpret the relation between the ...
Will's user avatar
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4 votes
2 answers
1k views

Why do we care about the canonical commutation relations?

Suppose $\hat{x}$ and $\hat{p}$ are the position and momentum operators, it can be shown that $$[\hat{x}, \hat{p}] = i\hbar\mathbb{I}.$$ The Stone-von Neumann theorem tells us that that the above is ...
CBBAM's user avatar
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1 vote
3 answers
4k views

Constants of motion in quantum mechanics

What is the meaning of a constant of motion in quantum mechanics (an observable-operator that commutes with the Hamiltonian) in contrary with classical mechanics?
Constantine Black's user avatar
4 votes
2 answers
476 views

Whence the $i$ in QM Poisson bracket definition?

On p. 87 of Dirac's Quantum Mechanics he introduces the quantum analog of the classical Poisson bracket$^1$ $$ [u,v]~=~\sum_r \left( \frac{\partial u}{\partial q_r}\frac{\partial u}{\partial p_r}- \...
daniel's user avatar
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2 votes
2 answers
1k views

Commutator and Order of Measurement

I was going through Prof. Leonard Susskind's lectures on Quantum Field Theory (Lec 2). Professor said that the commutator of two observables $AB-BA$, has nothing to do with the 'measurement'- B ...
Seeker's user avatar
  • 592
8 votes
1 answer
503 views

Similarity between unitary operators and ladder operators

I observed a similarity. Is this a co-incidence?: $$(I+\epsilon P)|x\rangle =|x+\epsilon\rangle$$ And, $$(X+iP)|n\rangle=A_n|n+1\rangle$$ Here, $|x\rangle$ is an eigenfunction of position. $|n\rangle$ ...
Ryder Rude's user avatar
  • 6,790
3 votes
1 answer
1k views

The Physical Meaning behind a Commutator [duplicate]

I've just been introduced to the idea of commutators and I'm aware that it's not a trivial thing if two operators $A$ and $B$ commute, i.e. if two Hermitian operators commute then the eigenvalues of ...
Ari Ben Canaan's user avatar

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