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A 6500-kg helicopter accelerates upward at 0.60 m/s² while lifting a 1200-kg car. (a) What is the lift force exerted by the air on the rotors?
(b) What is the tension in the cable (ignore its mass) that connects the car to the helicopter?

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Force = (Mass)*(Acceleration)

Use the above equation to:

1.) find the force required to accelerate the helicopter and car 0.60 m/s² (NOT upward)

2.) find the force required to counteract the acceleration due to gravity (9.8m/s²) for both the car and the heicopter

3.) adding 1. and 2. together will equal the lift force exerted by the air on the rotors

4.) do the same thing as in 1-3 except for only the car, which will yield the tension in the cable.

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