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As far as I understood, Fermi's golden rule gives a prediction of the transition rate in a perturbed quantum system $H_0+V$ between two eigenstates of the unperturbed system $H_0$, say from $\left| i\right>$ to $\left| f\right>$ with eigenenergies $E_i,E_f$. The prediction is perturbative in the first order of $V$.

The result is, that the rate equals

$$\gamma_{i\to f} = 2\pi |\left<f|V|i\right>|^2 \delta(E_i-E_f)$$

This rate is defined as $$\gamma_{i\to f}=\frac{d}{dt} |\left<f|U(t)|i\right>|^2.$$

My question: How should one interpret this differential "rate" physically?

My thoughts so far: Apparently it is the derivative of the transition probability with respect to time, so it is not a probability itself. In literature it is often called decay rate, but for an exponentially decaying probability $p(t)\sim e^{-\lambda t}$ the decay rate $-\lambda$ would not be computed as $dp/dt$, but $(dp/dt)/p$.

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    $\begingroup$ Spontaneous emission. $\endgroup$ Commented Feb 12, 2014 at 9:46
  • $\begingroup$ @ChrisGerig I dont get your comment, can you explain it in more detail? $\endgroup$
    – flonk
    Commented Feb 12, 2014 at 10:32
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    $\begingroup$ google "fermi golden rule and spontaneous emission", this is standard stuff in the literature $\endgroup$ Commented Feb 12, 2014 at 19:10
  • $\begingroup$ Possible duplicates: physics.stackexchange.com/q/89402/2451 and links therein. $\endgroup$
    – Qmechanic
    Commented Mar 7, 2014 at 18:29

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