0
$\begingroup$

This question already has an answer here:

I can't figure out what kind of connection it would be if i put resistors like thisenter image description here

Can someone please explain how they are connected, like is R1 and R2 in series and R4 and R5 in series and then I make a parallel of R12 and R45 and R3?

And what if I replaced R3 with a capacitor would it be connected in parallel with these resistors so I could get the charge on the capacitor by doing $q = C * U$

$\endgroup$

marked as duplicate by jinawee, Qmechanic Feb 11 '14 at 15:01

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

  • $\begingroup$ Possible duplicates: physics.stackexchange.com/q/22252/2451 and links therein. $\endgroup$ – Qmechanic Feb 11 '14 at 15:01
  • $\begingroup$ This cannot be reduced to any simple series-parallel combination and you need to use Kirchoff's laws to find the current flowing in the branches. A special case of this circuit which is easy to handle is the wheatstone bridge. $\endgroup$ – Sandeep Thilakan Feb 11 '14 at 15:11