Does an athlete's proficiency at luge depend on his mass? I was watching the men's luge ride with my dad. My dad said, the mass of the athlete must be at an optimum level so that he wins. I said, his volume should be minimum, but it has nothing to do with the mass, as the acceleration is independent of mass.
Is it just like any other "block on an incline" problem? Or am I wrong?
 A: It has to do with drag of the air.  This is related to the surface to mass ratio.  The surface of a sphere increases with the square of the radius while mass increases with the cube.  So the surface to mass ratio is proportional to $r^2/r^3 = 1/$r.  This means that overweight lugers would have a big advantage.  They don't want that, so lighter lugers are allowed to wear weights to decrease their surface to mass ratio.  A luge official told me this.
A: The acceleration equation needs to include force terms for air drag $F_a$, and runner friction $F_f$ in addition to the gravity term $g \sin(\theta)$ where $\theta$ is the slope of the luge run and $g$ is gravitation.  
As Singh pointed out, gravitation exerts a force proportional to mass, so the total acceleration is
$$a = g \sin(\theta) - \frac{F_f + F_a}{m}$$
Runner friction is more or less proportional to mass, so we can replace it with a constant, i.e. the mass of the rider is not a consideration, giving
$$a = g \sin(\theta) - K - \frac{F_a}{m} $$
Air drag depends on frontal surface area, $A$ and the square of velocity $v^2$, so
$$F_a = DAv^2$$ where D is a drag coefficent to account for the rider's aerodynamic smoothness (or lack thereof).  
User11865's answer points out that the rider's surface area is proportional to $\sqrt{m}$ and this is what gives heavier riders an advantage, especially at higher speeds.  Let's wrap the density and shape of the human body into a constant, say, $B$, and the acceleration equation now looks like
$$a = g \sin(\theta) - K - \frac{DBv^2}{\sqrt{m}}$$
The acceleration lost to air drag is the only term that depends on mass and having more mass makes it smaller.  
A: This should probably be a comment or an edit to the question, but, for now, I'll post it as a community wiki answer. (Also, you will note there's no physics here.) These are quotations from the "Luge: Nutrition Fact Sheet" by the U.S. Olympic Committee - Sport Performance Division. (I found it through Googling heaviest luge competitor, first hit, but I cannot get the direct link.) I think it is from 2010.

Body Composition:
Power to weight ratio is key. The ideal body composition is a
  large lean mass with high levels of muscularity in the upper
  body. Given the explosiveness required at the start of a run,
  athletes will utilize mostly fast twitch muscle in the upper
  body. While it is known that a high power to weight ratio is
  important for the start, there is a debate on what the optimal
  total mass should be. The debate is whether an athlete
  should be lighter to benefit during the start or if an athlete
  should be heavier to benefit from gravitational pull during the
  run. It has been hypothesized that a .01s advantage on the
  start will multiply into a .03s advantage in the end. However,
  there is still a culture that pressures athletes to gain any type
  (fat and lean mass) of weight to increase total mass.
Body Mass. Our US luge athletes are smaller and lighter
  than ther international competitors. The debate over lighter
  mass for the start versus greater mass for the run remains;
  and athletes have been historically pressured to gain weight
  for performance. The sport science team should play a role
  in this decision as to what will maximize performance.

Perhaps it should be noted that the US doesn't have a stellar Olympic record at the luge. :)
This is just to point out, that your question is a good one.
A: I think you are wrong because volume do not have any relation with acceleration, but the cross-sectional area have an effect on acceleration, as more the cross-sectional area more will be the drag and so the retarding force.
The other thing you said that acceleration is independent of mass is also wrong, you know that 
$$F=ma$$
$$\implies a={\frac{F}{m}}$$
Now from here it is clear that as mass decreases acceleration increases for the same amount of force.
As you dad said that mass must be optimum, I cannot provide its scientific reason because I have not learned optimization but you can get an idea(verification) of it by watching this video.
Link: https://www.youtube.com/watch?v=nPLx9j-bBHo
Between 21:00 - 22:00 min
Do watch the video.
