Suppose one considers a multi-component free fermions field theory with field $\psi_{q_i}$ with a give global symmetry (such as U(1)). We can say that every component of fermions carry some U(1) charge $q_i$. Now, let us introduce Yukawa-Higgs term to mediate fermion-fermion interactions. Explicit Higgs charge are assigned to maintain the U(1) symmetry in Yukawa-Higgs term. We also consider the Higgs field strongly-disordered so do NOT break global symmetry (here U(1)) via the normal Higgs mechanism. This can be done by adding kinetic terms to Higgs field, and in principle $\langle \Phi \rangle=0$ but $ (\Phi-\langle \Phi \rangle)^2\neq0$, i.e. the Higgs field does not condense, but Higgs field strongly fluctuates.
Here is the Question:
whether including all symmetry-allowed Yukawa-Higgs term of a single Higgs field ($\Phi$) can induce any symmetry-allowed multi-fermion interactions?
I can imagine this may be true if we have:
including all symmetry-allowed Yukawa-Higgs term of (multi-component and multi-species) Higgs fields ($\Phi_1$,$\Phi_2$,$\Phi_3$,$\Phi_4$,$\dots$)
$\Leftrightarrow$ (iff: correct?)
induces all symmetry-allowed multi-fermion interactions.
But let us say if we have only ONE single component scalar Higgs field, say all symmetry-allowed Yukawa-Higgs term of $\psi_{q_i}^{n_i} \Phi^{m} \psi_{q_j}^{n_j}$ (with $\psi$ are fermions field and $\Phi$ is the only Higgs, with some power ${n_i},{n_j},m$ perhaps with complex conjugate $(\psi_{q_i}^{\dagger})^{|n_i|}$ if ${n_i}<0$.) can one prove or disprove this is true or no that it can generate all multi-fermion interactions, such as $$V_{interaction}=\big( ({\psi}_{q_1} \nabla^1_x {\psi}_{q_1} \nabla^2_x {\psi}_{q_1} \dots \nabla^{N_{q_1}}_x {\psi}_{q_1}) \dots ({\psi}_{q_n} \nabla^1_x {\psi}_{q_n} \nabla^2_x {\psi}_{q_n} \dots \nabla^{N_{q_n}}_x {\psi}_{q_n}) \dots ) \big) + \text{hermitian conjugate}$$ with potential higher derivative terms?
