Frequency modulated waves are less susceptible to noise compared to amplitude modulated signal. This is because the information in an FM signal is transmitted through varying the frequency, and not the amplitude. But why does noise affect changing amplitude and not frequency or other characteristics?


2 Answers 2


The idea that frequency modulated signals are more resilient to noise than amplitude-modulated ones is somewhat of a myth. Both are susceptible to noise: the demodulation sequence (including the human hearing and sight senses) reacts slightly differently to the effects of noise so that.

It can be shown that if there is additive Gaussian noise with frequency much less than the carrier frequency, one can resolve a signal, through the slowly varying envelope approximation, into in-phase and quadrature components as sketched in my drawing below:

Noise Resolution into In-phase and quadrature components

I represent the carrier $\cos(\omega\,t)$ as an $x$-(horizontal) direction phasor: an additive, narrowband Gaussian processes can be resolved into uncorrelated, zero mean Gaussian processes $n_x(t),\, n_y(t)$ with equal variance $\sigma^2$. We define the amplitude of the carrier to be one unit. An AM signal with rms modulation depth $\mathcal{M}$ has a signal of strength $\mathcal{M}^2$: the signal to noise ratio is:

$$\mathcal{S}_{AM} = \frac{\mathcal{M}^2}{\sigma^2}$$

Now the phase of the carrier is perturbed by a noise signal: with a slowly varying envelope approximation, the phase noise signal is $$\phi(t)\approx n_Y(t)$ radians.

So if a phase modulated signal has an rms phase deviation of $\beta$ and if this deviation is less than a radian, then the signal to noise ratio for a phase modulated signal is:

$$\mathcal{S}_{PM} \approx \frac{\beta^2}{\sigma^2}$$

Given the phase perturbation is $n_Y(t)$ radians, the frequency perturbation is $\mathrm{d}_t n_Y(t)$. So both AM and FM (and more generally, phase modulated signals) are affected by noise and for small signals a signal with rms phase modulation of $\beta$ radians is exactly as susceptible to noise as an AM signal with a modulation index $\mathcal{M}=\beta$

To understand the effect on larger amplitude FM signals, we use the generating function identity for Bessel functions of the first kind to expand the signal $\cos\left(\omega \,t + \sqrt{2}\beta \cos(\omega_s t + \delta)\right)$ as a Fourier series to find that this is roughly the same as an AM signal (i.e. one looks at the first harmonic) with a modulation index $\mathrm{J}_1(\beta)/\mathrm{J}_0(\beta)$. So an FM or PM signal with rms phase modulation of $\beta$ radians is exactly as susceptible to noise as an AM signal with a modulation index $\mathcal{M}=\mathrm{J}_1(\beta)/\mathrm{J}_0(\beta)$.

There is also a perceived difference in the demodulated noise owing to the different technologies used to demodulate the signals. Phase locked loops tend to smooth out noise for modest noise levels, but fail catastrophically every now and then by cycle slipping. So noise on an FM signal tends only to be noticed as "burst" events. So for signal to noise ratios down to about 100 (amplitude ratios down to 10), FM audio seems better than AM of the same signal to noise ratio. However, at worse signal to noise ratios, FM fails altogether and is practically useless, whereas an audio signal sent by AM can still be understandable at 5dB SNR.

Another way to think about this is that FM signals encode their message in the zero crossing times. So your message is encoded in the instantaneous frequency, which is well approximated by $1 / (t_{j+1} - t_j)$, where $t_j$ is the time when the FM wave crosses the zero voltage level. So imagine you are the demodulator and you're waiting for the next zero crossing, and suppose the next one isa downwards zero crossing. If we the noise adds a little bit to the signal in the positive direction, it will then take a bit longer for the signal to make its next zero crossing than it otherwise would without the noise. If the noise is negative, it bumps the signal downwards, and so the next zero crossing time seems to come early. The inferred instantaneous frequency is then in error. Noise that "adds" obviously corrupts AM signals, but it also bumps the signal wave up and down and also corrupts the zero crossing times and thus also corrupts FM signals too.

  • $\begingroup$ Thank you for your answer. Though I got the idea I was not able to fully understand the math part as I'm unfamiliar with Gaussian noise,Gaussian processes etc(it's not taught in high school). $\endgroup$ Jan 19, 2014 at 4:45
  • $\begingroup$ @RajathKrishnaR Try the last paragraph on for size! $\endgroup$ Jan 19, 2014 at 23:36
  • $\begingroup$ For pre-detection carrier power to noise power ratio CNR>100 (20dB) FM is always better than AM if for nothing else but for the amplitude limiter preceding the frequency discriminator. The limiter removes the amplitude noise that is 1/2 of the noise the other 1/2 being the phase noise. Cycle slipping probability is practically nil when CNR>20 (13dB). $\endgroup$
    – hyportnex
    Jan 20, 2014 at 0:12
  • $\begingroup$ @user31748 Thanks for the info - you clearly are a bit more up with the practical issues for FM than I am. However, are you sure of your comment "...if for nothing else but for the amplitude limiter preceding the frequency discriminator. The limiter removes the amplitude noise that is 1/2 of the noise the other 1/2 being the phase noise."? One can argue that the quadrature noise $n_y(t)$ in my diagram affects an FM signal stronly but an AM signal weakly, as well as the "symmetric" argument that the in-phase noise component $n_x(t)$ affects an AM signal strongly but an FM signal weakly. ... $\endgroup$ Jan 20, 2014 at 1:33
  • $\begingroup$ @user31748 ... so it would seem from my simple minded reasoning that both signals are, to first order, only affected by half the noise power: the half that affects one doesn't affect the other. $\endgroup$ Jan 20, 2014 at 1:36

What really makes FM better than AM is that after the limiter there is the frequency detector, the "discriminator", that is effectively a differentiator. Using your diagram with the assumption that the amplitude is 1 the phase error is $\phi$ ~ $n_y$ whenever $|n_y|<<1$ (above threshold condition, in practice meaning CNR>10dB). Thus the FM noise or frequency error being the time derivative of this phase error, is $\delta f$ ~ $\frac{dn_y}{dt}$ the spectrum of which is thus proportional to $f^2$. This is zero at dc and most FM systems take advantage of this because most signals have their spectral content concentrated around dc and declining at higher frequencies. The high frequency noise beyond the signal's spectrum is removed by a low-pass filter following the discriminator. Further SNR improvement relative to AM can be had by actually predistorting the spectrum of the baseband signal by passing it through a simple high-pass filter before frequency modulation (pre-emphasis) so that the higher frequency spectral content is amplified relative to the lower frequencies. This pre-emphasis attempts to match the post-detection noise spectrum that is proportional to $f^2$. Matching here means that the signal's spectral density to the noise's spectral density ratio be approximately constant across the bandwidth of interest. After this filtering the signal and the remaining noise are passed through a low-pass filter (de-emphasis) to restore the original signal spectrum. (Of course these two filters can be combined into one.)


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