# Riemann normal chart and special relativity

When you pick Riemann normal coordinates at a point, then the Christoffel symbols vanish and the metric is flat, but the Riemann curvature tensor does not necessarily vanish. Since Einstein said that locally the laws of special relativity hold, how does that reconcile with the Riemann curvature tensor not being zero (which means that spacetime doesn't appear to be flat in that local neighborhood)?

At a specific space-time point , you could always find a inertial frame, such that the metrics is Minkowski at this point (say at $x=0$ in this inertial frame), but this does not mean, that the metrics is Minkowski for $x \neq 0$, in fact, you may made a Taylor series around $x=0$ and you find :
$g_{\mu\nu}(x) = n_{\mu\nu} + \frac{1}{3} R_{\mu \alpha\nu\beta} x^\alpha x^\beta + O(x^3)$
$\Gamma_{\alpha \beta}^\mu(x) = -\frac{1}{3} (R^\mu_{\alpha\beta\nu} + R^\mu_{\beta\alpha\nu})x^\nu + O(x^2)$