# How much heat needed to heat 400g of ice at 0°C to 20°C in a 200g aluminium pot? [closed]

An aluminium pot has a mass of 200g and contains 400g of ice at 0°C. How much heat would be needed to melt that ice and then raise the temperature of the resulting water to 20°C. The specific heat capacity of water and aluminium are 4200 J Kg ^-1 and 910 J Kg ^-1 respectively, and the latent heat of fusion of ice is 330 KJ/Kg.

My attempt so far is as follows:

Heat from ice to water - Q = mL = .4Kg x 330x10^3J = 132x10^3J

Heat for water from (0°C to 20°C) - Q = mcΔT = .4Kg x 4200 x (20-0) = 33.6x10^3J

Heat for pot from (0°C to 20°C) - Q = mcΔT = .2Kg x 910 x (20-0) = 3.64x10^3J

Thus the answer is 3.64x10^3J + 33.6x10^3J + 132x10^3J = 169.24x10^3J

I don't know how to do this question but would try go this way about it, however it looks terribly wrong to me and would like some help please.

## closed as off-topic by David Z♦Jan 11 '14 at 23:36

This question appears to be off-topic. The users who voted to close gave this specific reason:

• "Homework-like questions should ask about a specific physics concept and show some effort to work through the problem. We want our questions to be useful to the broader community, and to future users. See our meta site for more guidance on how to edit your question to make it better" – David Z
If this question can be reworded to fit the rules in the help center, please edit the question.

• Why does it look terribly wrong? Your $0-20$'s should be \$20-0's (minus, not to) The message that the big number is melting the ice is correct. – Ross Millikan Jan 11 '14 at 23:39
• Thanks for the feedback. I guess it looks wrong because I don't know the correct way to approach the question and I just doubted my attempt. Is the rest incorrect? @Ross Millikan – user37216 Jan 11 '14 at 23:51
• You approached exactly correctly. I didn't check the numbers too carefully, but they look right – Ross Millikan Jan 12 '14 at 0:16
• Oh, that's great news. As long as the method was correct. thanks a lot for the help bro. – user37216 Jan 12 '14 at 2:15