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Now normally (if it was a block not rotating) all you would have to do is use $w^2 = k/m$ and $E= \frac12k(A\cos(2wt+\theta))^2 + \frac12m(Aw\sin(wt+\theta))^2$ or in other words the translational kinetic and spring potential.

But here I don't even know how to start.

Please could someone set up what I have to do?


closed as off-topic by David Z Dec 10 '13 at 20:59

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You want to use energy conservation still. The total energy of the system is still $\frac{1}{2}kd^2$. The difference here is that you will have an extra term in your kinetic energy due to the rotation.


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