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enter image description here

Let me explain the picture just to make sure. Object with mass 2 kg is being pulled with a force of F = 14.4 N. The whole system has an acceleration of a = 2.8 m/s^2. The friction coefficient between the objects and the ground is k = 0.2 What is the tension in the rope? So the question is simple I believe but I can't understand the concept of tension in the rope (red line). Also if it helps I have a solution for the problem, it says that the tension is 4.8 N. Can someone please elaborate this? Thank you!

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closed as off-topic by Waffle's Crazy Peanut, tpg2114, Qmechanic Nov 6 '13 at 15:42

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First try to think what are the forces acting on block with mass 1kg .The forces in horizontal direction are:-

1.friction

2.tension from rope

Now tension is something very common ,you just take a rope and hang a object from it ,it does not fall because tension balances the force of gravity.Basically all you need to produce tension is a rope and a pulling mechanism and you produce tension at the other end.

Since you know the acceleration of this block you can apply F = ma and find the tension.

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  • $\begingroup$ I'm sorry but I don't understand your answer to the problem with the blocks. Can you please show the calculation ? $\endgroup$ – user1949350 Nov 6 '13 at 15:30
  • $\begingroup$ please be more specific about what you don't understand $\endgroup$ – Sahil Chadha Nov 6 '13 at 15:33
  • $\begingroup$ How to calculate the tension. Apparently, it's equal to 4.8 N. No matter what I do I can't get that result. $\endgroup$ – user1949350 Nov 6 '13 at 15:37
  • $\begingroup$ (tension)-(friction)= (1) * (2.8),friction=0.2*1*10 $\endgroup$ – Sahil Chadha Nov 6 '13 at 15:39
  • $\begingroup$ lol i was doing something totally different trying to get the net force on one side and on the other and then add that up. Thank you a lot! $\endgroup$ – user1949350 Nov 6 '13 at 15:43

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