It is often said that the Bell test disqualifies "local realistic"
theories from quantum physics.
This implies that there are 3 out of 4 classes of theories from the following list that can be compatible with the outcomes of quantum experiments:
Class 1) Local & realistic.
Class 2) Local & non-realistic.
Class 3) Non-local & realistic
Class 4) Non-local & non-realistic.
A lot of people feel uncomfortable with rejecting non-locality, as they (possibly incorrectly) feel it flies in the face of Special Relativity, so they come up with theories that fit into class 2 to try and preserve locality. Personally, since it can be demonstrated that the non-locality of quantum physics does not result in the possibility of superluminal communication at the macro level, it does not bother me in the slightest.
Of course, a lot depends on what we mean by realism. I do not think anyone has ever produced a comprehensive, definitive list of the properties a theory must have in order to be qualified as a realistic theory. Some such lists might include the following:
a) A particle has a definite state at any instant.
b) There is a single universe.
c) Retro-causality is not allowed.
d) The future cannot be predicted with 100% certainty.
e) The evolution of the universe cannot be rewound to a past event, deleting the history of that evolution and then replayed again to create a different history.
... and so on. These properties in this list might be called elements of reality. Casting out any given element does not automatically result in a valid local theory that is consistent with quantum mechanics. Discarding element (a) on its own can not result in a valid local theory. MWI obviously discards element (b) and probably elements (c) and (e) as well. Element (d) is controversial and debatable. Some might argue that element (d) is not an element of reality and that a realistic theory requires that with full knowledge of current conditions, we can predict the future with $100\%$ certainty. Super determinism is a theory that rejects the element of reality (d) and, indeed, such a theory does not require non-local influences and means we have to give up notions of free will. Pilot wave theory or Bohmian mechanics rejects element (c).
Any sensible discussion or analysis of Bell's test requires we define a clear definition of the elements of reality that qualify a theory to be called a realistic theory. (Not necessarily my list).
The conclusion of nonlocality is not independent of realism; in fact,
it follows from the denial of realism.
Class 3 type theories (Non-local & realistic) can be consistent with quantum mechanics and do not require the rejection of realism in order to have a consistent and valid non-local theory that agrees with the observed outcomes of real quantum experiments.
Here is an "in your face" quantum thought experiment that makes it obvious that in this experiment, any explanation cannot be both non-local and realistic.
The set-up is very simple, so relatively immune to hand-waving obfuscation. Ann and Bob have polarising analysers, and they are spacelike separated. Each analyser has two detectors. If a photon is detected at detector $\text{H}$, we call the result $1$, and if detected at detector $\text{V}$, we record a $0$ result. We also record the time of detection and the orientation of the analyser for Ann's analyser ($\theta_A$) and Bob's analyser ($\theta_{\text{B}}$). Entangled photon pairs are prepared in orthogonal polarised states and sent in opposite directions to Alice and Bob. Alice and Bob are allowed to rotate their analysers to any position at any time and then read off their results when an entangled photon is received. Quantum mechanics predicts that the correlations of Ann and Bob's results will be $\sin^2(\theta_{\text{A}}-\theta_{\text{B}})$. Any purely local interpretation has to explain how the angle of Ann's analyser ($\theta_{\text{A}}$) is known at Bob's location when Ann and Bob are spacelike separated. It is as simple as that.
Imagine a third party ($\text{C}$) that prepares the entangled photons, and this third party has full knowledge of the sent photons. Let's imagine that when $\text{C}$ sends a vertical photon to Bob, he also sends a message saying: "I have sent you a vertical photon, and I have sent Ann a horizontal photon." When Bob receives the message, he knows the position of his own analyser ($\theta_{\text{A}}$), and he has full knowledge of the states of both the entangled photons at the time of emission, but he still cannot determine the outcome of $\sin^2(\theta_{\text{A}}-\theta_{\text{B}})$ even with full knowledge of the photons states at preparation because he does not know $\theta_{\text{A}}$. Therefore, realism does not rule out non-locality, in this case.
Or are those who insist that realism can be rescued by denying
locality simply wrong?
They are not wrong. With non-locality, it does not matter if the theory is realist or not; the theory can be valid either way (Class 3 & 4 type theories.) It insists that the theories are local in nature and require realism (a reasonable description of reality) to be sacrificed.
For example, if Bob has non-local information about the position of Ann's polarising analyser ($\theta_{\text{A}}$) and combines this with his local knowledge of the position of his own analyser ($\theta_{\text{B}}$) then he has all the information he needs to determine the outcome using the correlation relationship $\sin^2(\theta_{\text{A}}-\theta_{\text{B}})$ and this does not rule out realism, but neither does it require it.
Such a realist would simply say entanglement phenomena result from
particles having anti-correlated values "from birth", which
measurement simply discovers. They have no need for nonlocality. –
Michael Pierce
The problem with this approach is that it simply does not work and does not reproduce the results of quantum mechanics as observed in laboratories.
We could list locality as an element of reality (i.e. no event can be influenced by another event that is not in its past light cone), and using this definition, we can cut down Bell's theorem to "No realist theory can reproduce the predictions of quantum mechanics". To reproduce the results of quantum experiments, we have to throw out at least one element of what we would normally call a reasonable description of reality.
The Bell test shows that the inequality is indeed violated; therefore,
we are committed to non-realism, while EPR shows that we are thereby
also committed to non-locality
You have not explained how you have reached your conclusion. Bell's test allows for the existence and validity of Class 3 type theories (non-local & realistic), so we are not committed to non-realism and also allows for the existence and validity of Class 2 type theories (local & non-realistic), so we are not committed to non-local theories.
KDP I would be extraordinarily interested! ....In any case, what you
described is essentially what I'm after, but my (mis)understanding of
Bell's Theorem is holding me back. I have no qualms with nonlocality,
but I really do not like nonrealism (in the sense of things not having
pre-measurement values). And people keep saying these are independent
of each other, but that doesn't make sense to me, for the reasons
given above. – Michael Pierce
As promised, here is a description where the photons have definite pre-measurement values:
The set-up: There are 3 ways to prepare entangled polarised photons using Parametric Down Conversion, and it is possible to prepare entangled polarised photons that have the same polarisation as each other. Type II SPDC, where the photons are prepared orthogonal to each other, is cheaper and less fiddly, and that is why is most often used in labs and descriptions of experiments. Having the photons prepared parallel to each other is easier to visualise, and that is what I will use here. This means the quantum predictions for the correlation outcomes are according to $\cos^2(\text{A}-\text{B})$ where $\text{A}$ and $\text{B}$ are the orientations of Ann and Bob's analysers, respectively. They both have polarising beam splitters that they use as their polarising analyser. Each beam splitter sends a photon to one of two detectors. One detector indicates the photon was polarised parallel to the optical axis of the beam splitter, and the other detector detects photons that were orthogonal to the optical axis. If a photon is at $45^\circ$ to the optical axis, there is a $50:50$ chance that it will either go to the parallel or the orthogonal detector of the analyser assembly.
There is no requirement to assign a non-detection to an assumed orthogonal detection as would be required for an ordinary polarising filter. Classically when a photon is polarised at $45^\circ$ to the vertical passes through a vertical polarising filter, $50\%$ of 'the light' passes through and $50\%$ is absorbed by the filter. Quantum mechanics says each individual photon either passes through the filter or is wholly absorbed by the filter. The $50\%$ diminution of intensity in quantum mechanics is a statistical summation due to $50\%$ of the individual photons passing through and $50\%$ being absorbed. This probabilistic nature of polarising filters is unavoidable and not up for debate because it is observed in a single polarising beam splitter analyser without involving entanglement or anything fancy like that. For our purposes, here, a detection on the parallel detector is assigned a value of "$1$", and a positive detection of the detector orthogonal to the optical axis is assigned the value "$0$". Either way, the polarising analysers must obey Malus' law. This dictates that if a given photon has an orientation of $\theta_p$ relative to the vertical and the analyser has an orientation of $\theta_a$ relative to the vertical, then the probability of getting a "$1$" result is $\cos^2(\theta_p -\theta_a)$. Alice and Bob are free to rotate their analysers to any position.
Sample run 1: Let's assume at the time of reception, both Ann and Bob's analysers are vertical. QM predicts that the correlation of their results must be unity. Also, assume that the entangled photons are initially orientated at $45^\circ$ from vertical "at birth". Classically, we would expect there to be a $50:50$ chance of getting a $1$ at Ann's analyser and a $50:50$ chance of getting a $1$ at Bob's analyser. There is a chance that their results do not correlate and do not agree with QM. In the non-local interpretation, whatever happens to one entangled photon instantly also happens to the other entangled photon. This is what allows the realism philosophy to reproduce the predictions of QM. If the photon going to Ann's analyser is rotated to the vertical as it passes through her analyser, then she gets a result of "$1$" and instantly, the photon going to Bob's analyser rotates to the same vertical position and is guaranteed to pass through Bob' vertical analyser and produce a "$1$" result. If on the other hand, the photon passing through Ann's analyser is rotated to horizontal (which has a $50\%$ chance of happening), giving a "$0$" result, then the photon approaching Bob's analyser instantly rotates to horizontal and has a $100\%$ probability of being detected as a "$0$" result on Bob's analyser. This means Ann and Bob's detections will be $100\%$ correlated as demanded by QM. Whether one of the photons arrives at Ann or Bob's analyser first does not change the outcome. It is immaterial.
Note that at every moment, the photons have a definite state and location except when they are scrambled at the polarising filters, but after passing through, they have a new but definite orientation. However, when we look at the results, we cannot exactly determine the original orientation of the photons. Nor can Ann or Bob determine the orientation of the other's analyser at the time of reception. While having an exact state at the time of creation is not incompatible with QM, we can not measure that exact state. The so-called superposition of states of the photons in travel can be thought of as a reflection of our inability to measure their exact state.
Sample run 2: Let's assume at the time of reception, Ann's polariser is vertical and Bob's analyser is horizontal. QM predicts that the correlation of their results must be zero. Also, assume that the entangled photons are initially orientated at $45^\circ$ from vertical "at birth". Classically, we would expect there to be a $50\%$ chance of Anne getting a "$1$" at her analyser and a $50\%$ chance of Bob getting a "$1$" at his analyser. If they both get a "$1$", this would be a contradiction with the QM expectation.
Once again, the situation is saved by allowing non-local interaction of the entangled photons. If the photon going to Ann's analyser is rotated to the vertical as it passes through her analyser, then she gets a result of "$1$" and instantly, the photon going to Bob's analyser rotates to the same vertical position and is guaranteed not to pass through Bob' horizontal analyser and produce a "$0$" result. If on the other hand, the photon passing through Ann's analyser is rotated to horizontal (which has a $50\%$ chance of happening), giving a "$0$" result, then the photon approaching Bob's analyser instantly rotates to horizontal and has a $100\%$ probability of being detected as a "$1$" result on Bob's analyser. This means Ann and Bob's detections do not agree, and there is a $0\%$ correlation in agreement with the expectations of QM.
Sample run 3: Let's assume at the time of reception, Ann's analyser is vertical, and Bob's analyser is $30^\circ$ from the vertical. QM predicts that the correlation of their results must be $\cos^2(0-30) = 0.75$. Let's assume the prepared entangled photons are both initially orientated at 60 degrees from the vertical. On arrival at Ann's analyser, Ann's photon has a $\cos^2(60-0) = 0.25$ probability of being detected as a "$1$". If it is detected as a one, Bob's photon is immediately rotated to the vertical position and, on passing through Bob's analyser, has a $0.75$ chance of being detected as a "$1$". Ann's photon also has a $0.75$ probability of being detected as a "$0$" and if that was the case, then Bob's photon would have been rotated to $90^\circ$ from vertical. The photon going towards Bob's analyser would now have a $\cos^2(90-30) = 0.25$ probability of being detected as a "$1$" and a $0.75$ chance of being detected as a "$0$". This means if Ann detects a "$0$", there is a $75\%$ chance that Bob also receives a "$0$". If Ann detected a "$1$", there is also a $75\%$ chance Bob also detected a "$1$". Overall, the chance they either both receive a "$1$" or both detect a "$0$" is $75\%$, which agrees with the correlation probability predicted by QM.
This means we can take a realistic position of asserting the entangled photons have a definite state when created, and the outcomes would not be incompatible with QM, but unfortunately, we can not have everything. We have accepted that taking a measurement with the analysers alters what we are measuring and that the outcome of passing through an analyser is probabilistic in nature, and, of course, this analysis assumes that there is a non-local connection between the entangled photons. Without the non-local connection, the correlations would not be consistent with the predictions of QM. It is interesting to note that the photons passing through Bob's analyser do not have to know the position of Ann's analyser. Without the non-local connection of the entangled photons, we would have to assume something drastic like invoking multitudes of invisible parallel universes or giving particles the ability to retroactively go back into the past and change the orientations of the emitted entangled particles or be able to predict the future positions of the analysers with $100\%$ accuracy.
Final note: Entangled particles are not the only quantum game in town that we have to explain. When we consider experiments based on Mach Zehnder interferometers, they are not explained by entanglement, and the Many Worlds Interpretation begins to gain traction here. That is a different story, though.