5
$\begingroup$

Imagine two electrons $A$ and $B$ at rest.

Electron $B$ is at a vertical distance $r$ above electron $A$.

Let us assume that the electrons are constrained to move on horizontal rails.

At time $t=0$ I give electron $A$ a horizontal acceleration $a$ for a time interval $\Delta t$.

At time $t=r/c$, due to the impulse provided by the classical Lienard-Weichert radiation field of electron $A$, electron $B$ gains horizontal momentum:

$$\Delta p = F\Delta t=-\frac{e^2a\Delta t}{4\pi\epsilon_0c^2r}$$

In terms of quantum electrodynamics a photon is exchanged between electron $A$ and electron $B$.

Therefore if electron $B$ receives a momentum $\Delta p$ from the photon does that mean that electron $A$ must recoil with momentum $-\Delta p$ as it emits the photon?

If this is true then the classical (retarded) Lienard-Weichert interaction theory describes (later) momentum transfer to the static charge $B$ due to the (earlier) accelerating charge $A$ but it neglects the fact that charge $A$ receives (earlier) recoil momentum during the process.

Maybe this recoil momentum is described by a time-reversed advanced Lienard-Weichert interaction in which the earlier momentum transfer to the accelerating charge $A$ is due to the later interaction with the static charge $B$?

$\endgroup$
1
$\begingroup$

In classical electromagnetism the force which is responsible for the recoil due to radiation of EM wave is called Abraham-Lorentz force.

Since it is proportional to $\dot{\mathbf{a}}$ in your example it will be felt by electron $A$ as a jerk at the start and end of interval $\Delta t$ and had to be compensated by whatever external force is used to provide acceleration.

This force accounts for EM waves emitted in all (allowed) directions and so, do not need subsequent interaction with electron $B$, although of course electron $B$ would emit its own (retarded) EM wave which could be additionally felt by electron $A$ later, when it arrives. Nevertheless, time-reversable interpretation of such recoil (and Abraham-Lorenz force), similar to what you are suggesting, is available within Wheeler-Feynman absorber theory

$\endgroup$
  • $\begingroup$ I'm sorry I use this unorthodox way to communicate with you. I erased my question about dark matter, because your comment made me remember and I realize how stupid the question was. But I wanted to tell you thanks for that comment. In fact, you are right about your guess. I even assisted to a whole winter school a few years ago about cdm. I have written that question in a weird moment of confusion, being tired. $\endgroup$ – Eduardo Guerras Valera Oct 28 '13 at 16:51
  • $\begingroup$ That's OK and you're welcome! $\endgroup$ – user23660 Oct 28 '13 at 17:00

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.