2
$\begingroup$

When talking about gamma ray or x-ray propagation in media, we usually talk about the mass attenuation coefficient, and we desire high density materials for shielding. This seems probabilistic: we increase the shielding to maximize the chance of EM radiation interacting with the media.

However, conductivity is a part of the attenuation coefficient. Why not use highly conductive materials? What justifies using high density lead over high conductivity?

$\endgroup$
  • $\begingroup$ "conductivity is a part of the attenuation coefficient" I don't believe that this is so at the frequencies that you are asking about or rather I don't believe that the conductivity or lack there of makes a significant contribution. $\endgroup$ – dmckee Oct 28 '13 at 3:03
2
$\begingroup$

Major mechanisms for depositing the energy is through Compton scattering and/or pair production -- the gamma photon "hits" an electron (or produces a pair), and ejects it, and then these electrons interact with the other atoms in the material and so on.

So the steps are:

  1. get the photon to eject one or more electrons,

  2. the electrons interact with the material via bremsstrahlung, which is more effective with higher density materials (and higher atomic numbers), to give off X-rays,

  3. Go back to (1) (i.e. the bremsstrahlung X/gamma-rays ionize other electrons)

Repeat until you get down to non-ionizing radiation.

Due to the cross section of the photon scattering processes you need a lot of depth to ensure that almost all of the photons and electrons in the cascade interact with, and stop in, the material. High density materials provide more opportunities, per unit distance, of having one of these discrete interactions. Also note that alot of the Compton scattering is off of electrons in the inner shells of the atoms, and do not involve the conduction band electrons. All of this is well described in terms of particle "ballistics" and does not involve inducing a normal, bulk, electric current in the material (which would be influenced by the conductivity).

Although classical evaluation of the skin-depth indicates that higher conductivity would be more effective, it ignores the quantum-mechanical effects that are relevant because a single gamma ray photon can have so much energy (relative to any of the energy scales that characterize the material).

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.