Consider a metal plate, on which a light of appropriate wavelength is incident such that it creates an interference pattern. The wavelength is chosen such that it can cause detectable photo-electric emission.
If we observe only the part of the metal where the light interferes destructively, two things can happen:
Due to the destructive interference(wave nature of light), there is no energy reaching that part so no photo-emission.
There are two photons reaching the destructive interface, so the electrons in the atom can interact with either of them and cause photo-emission.
Which one of the two will happen(Or will something entirely different happen)? Has this experiment been done before?