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I came across this question in my physics textbook (Gr12) and I was hoping someone could explain the solution to me

A ball is thrown horizontally off a building at $8.2\,\text{m}/\text{s}$. At a point $P$, the ball is moving $60°$ to the horizontal. Show that the ball's vertical velocity at $P$ is $14.2\,\text{m}/\text{s}$.

I did manage to come across a solution to the problem, that being $14.2 = 8.2\tan 60°$. But I don't understand why the ratio between the ball's vertical velocity to its horizontal velocity is used here.

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The horizontal velocity does not change during the fall. So the total velocity can be inferred from the angle given.

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