Why can we skate on ice? I have known the reason why skate can slide over ice is that water's melting curve in terms of pressure and temperature has a negative slope. If the pressure due to our mass increases sufficiently high, the ice starts to melt.
But someone says, according to latest research, it is not true because the time for which we pressure the ice is too short so the ice can't has enough time to melt.
Which is more reasonable between the two arguments?
 A: Decrease of the melting temperature with pressure increase is not enough to explain skating (I conducted the calculation myself, but please see http://scitation.aip.org/content/aapt/journal/ajp/63/10/10.1119/1.18028). AFAIK, skating can be explained by ice melting due to heating caused by friction.
EDIT(10/22/2013): OK, so let us use the Clausius-Clapeiron relation (http://en.wikipedia.org/wiki/Clausius%E2%80%93Clapeyron_relation ): $\frac{dP}{dT}=\frac{L}{T\triangle v}$. Let us assume that $\triangle  T=1K$, $L=334\frac{kJ}{kg}$ (http://en.wikipedia.org/wiki/Latent_heat#Specific_latent_heat ), $T=273K$, $\triangle v=10^{-4}\frac{m^3}{kg}$ (1 kg of water has a volume of $10^{-3}m^3$, and volume of ice is 10% greater than volume of water), so $\triangle P \approx1.22\cdot 10^7 Pa$. Let us also assume that the area of a skate is $S=1mm\times 30cm=3\cdot 10^{-4}m^2$ and the mass of the skater is $m=80kg$. Then the pressure exerted by the skater is $\frac{mg}{S}=\frac{80\cdot 9.8}{3\cdot 10^{-4}}\frac{N}{m^2}\approx 2.88\cdot 10^6 Pa$. Therefore, the skater exerts pressure on ice that is four times less than that required to decrease the melting point by 1 degree Celcius.
