The AdS/CFT correspondence refers to the "boundary" of AdS space but I'm a little confused about what this means. Typically, one writes the AdS metric in the form $ds^2= \frac{L^2}{z^2}(-dt^2+d\vec x^2+dz^2)$ and then refers to the point $z=0$ as the boundary.
In what sense is this a boundary? AdS is maximally symmetric and so I'd think that there wouldn't be any special regions of it, such as a boundary. Relatedly, I could calculate the Ricci scalar and I'd of course find that it's constant everywhere (so that $z=0$ isn't a special point, in particular) and so the point $z=0$ seems like it's just a artifact of choosing poor coordinates. It appears reminiscent of the coordinate singularity that occurs in the Schwarzschild metric as one approaches the Schwarzschild radius (when using Schwarzschild coordiantes).
So is it truly a boundary? Does it matter?