2
$\begingroup$

This is a question I would like to have an explanation with: It's in this PDF, question 9.

circuit

In that circuit, if switch 1 is closed, bulb A burns normally. If 2 is closed as well, do other lamps burn normally as well?

The answer is D: yes, both B and C, but why? Could somebody explain the steps in order to think? This is not homework (even though in principal it is) but I did this voluntarily on my own interest in how more advanced electrical circuits work.

$\endgroup$
  • 2
    $\begingroup$ It might be better if you put the circuit here (having quoted "In that circuit") Regarding your homework trouble, our tag still applies to such questions ;-) $\endgroup$ – Waffle's Crazy Peanut Oct 13 '13 at 20:29
  • $\begingroup$ I wish I could read z german. $\endgroup$ – mcodesmart Oct 13 '13 at 21:01
  • 2
    $\begingroup$ @Programmer looks like dutch to me. $\endgroup$ – user6972 Oct 13 '13 at 22:14
2
$\begingroup$

If you close both switches 1 and 2 and redraw the circuit, it will look like this

enter image description here

So bulbs A, B and C are connected in parallel. The current will flow in all the bulbs, all of them will be working

| cite | improve this answer | |
$\endgroup$
0
$\begingroup$

This seems like it is part of a contest, so I'll just give you a hint. There is nothing unusual about this circuit at all. Just redraw it with the two switches closed and you'll see it just looks funny because of how the grounds are drawn.

| cite | improve this answer | |
$\endgroup$
  • $\begingroup$ uhm so if only 1 is closed, no current flows through b c because of resistence or what? $\endgroup$ – user209347 Oct 14 '13 at 15:33

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.