0
$\begingroup$

Thanks for anyone that can help.

Say we have a rocket engine in the vacuum of space with exhaust velocity of 2,000m/s or more, but low pressure exiting nozzle, say 1-2psi. A wider nozzle engineered for space, with low exhaust pressure. The rocket is landing on an asteroid, a crater, a moon, whatever. Something with no atmosphere still in the hard vacuum of space.

The low pressure would seem to indicate that the exhaust gas does little damage because it is dispersed. The high velocity would seem to indicate that it would do damage because of its high kinetic energy. This contradiction is confusing me.

How much pressure, or velocity, is needed to do various kinds of damage to ground below?

Two other questions, if anyone feeling generous.

  1. How rapidly would heat dissipate from exhaust after leaving nozzle?

  2. Why would the exhaust leaving nozzle slow down as it approaches the ground?

I suspect the answer is very simple, to the main question.

$\endgroup$
4
  • 1
    $\begingroup$ Suppose you had a gun that shot little fast bullets. Suppose you had one that shot big slow bullets. How much damage would they do? It depends on how big, how fast, and what they hit. It is hard to answer. The answer is complex. $\endgroup$
    – mmesser314
    Commented Jan 5 at 3:14
  • $\begingroup$ The bullets are the same size here. The exhaust gas particles. They have low exhaust pressure exiting the nozzle, but high velocity. Any more insights? And thank you. $\endgroup$
    – Nomadicus
    Commented Jan 5 at 5:55
  • $\begingroup$ Nothing really on what you are asking. Here is a video on how rockets are optimized for vacuum or air. Are Aerospikes Better Than Bell Nozzles?. $\endgroup$
    – mmesser314
    Commented Jan 5 at 14:50
  • $\begingroup$ There was a probe that sampled an asteroid and was a loose pile of rubble weakly held together by its gravity. The probe gently touched down and nearly sank out of site. It blasted away lots of matter with very weak engines. $\endgroup$
    – mmesser314
    Commented Jan 5 at 14:51

1 Answer 1

0
$\begingroup$

A nozzle, even with low exit pressure, acts as an under-expanded nozzle when it operates in a vacuum environment like the lunar surface. The exhaust gas expands rapidly after leaving the nozzle, resulting in a radial flow rather than being confined. In this case, shear stress (tangential force) dominates over normal force (pressure), leading to erosion spreading outward instead of downward. Imagine a scenario where you land a lander in the Earth's environment and the Moon's environment with the same exhaust pressure, temperature, etc. For Earth conditions, the atmosphere confines the flow, and a crater is expected to form beneath the nozzle. On the Moon, the flow expands radially due to the vacuum, leading to erosion in a more lateral direction. This radial erosion was observed during the Apollo missions, where no crater was formed beneath the lander, but dust cast out radially at high speeds and damaged the Surveyor mission’s optical mirror, even though it was located away from the Apollo landing site. In short, due to vacuum environment it creates less damage than it would create in atmospheric conditions like Mars and Earth. Ofcourse, you need take care of ground conditions like compact, rocks, porosity, cohesive strength of soil, etc.

Because of the absence of air, the heat would dissipate more slowly than it would in atmospheric conditions. In space, the primary method of heat dissipation is radiation.

In vacuum conditions, the exhaust would not slow down. When you land on an asteroid or Moon, the gas expands radially, but still, the centre flow goes straight and creates a shock. You will be seeing a bow shock structure in the lunar environment (you can refer to this paper to learn more on how it forms: https://pubs.aip.org/aip/pof/article-abstract/33/5/053307/1076639/Modeling-of-dusty-gas-flows-due-to-plume?redirectedFrom=fulltext). These shocks cause the exhaust to slow down only after impinging on the ground, converting kinetic energy into heat, leading to localized erosion or heating.

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.